Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

General relationship for direction of E field at any given point

  1. Sep 22, 2009 #1
    I was going through my textbook, Introduction to Electrodynamics, and I came across this question that puzzled me. The book is really great by the way, I would highly recommend it. No, this isn't a homework question, it just got me thinking.

    For a finite line of charge (like a rod, for example), there should be a general relationship for the direction of the electric field no matter where point X is located with respect to the finite line of charge. What do you think this general relationship is?

    Lets assume it’s a finite line of positive charge. I think of the electric field (E-field) always pointing outwards. So if you take a point X directly above the finite line of charge, say centered, it’s going to point up. But what relationship can we use to describe this?

    I know you can take a bunch of little dq's and add them up, and the direction each one of those points as X can be added up as the direction of the E-field.

    Can we incorporate the right-hand-rule with this? No rush to answer I was just curious.
     
  2. jcsd
  3. Sep 22, 2009 #2

    tiny-tim

    User Avatar
    Science Advisor
    Homework Helper

    Hi Ravenatic20! :smile:

    I think you're trying to say that the direction of the field (which is what the question asks for) always points perpendicularly towards or away from the line.

    This follows from symmetry.

    (the right-hand-rule has nothing to do with this … there's no current in the line :wink:)
     
  4. Sep 23, 2009 #3
    tiny-tim, what you say is only if the charge is on an infinite line, but Ravenatic was talking about a finite line of charge.

    Anyway, this is a solvable problem. Ravenatic's method of integration is correct, just integrate up the charge density using Coulombs law and you get your E filed. I don't think the integration is trivial, but it can be done. BTW, the right-hand rule has no bearing on this, but it would be if the there was a line of current and you wanted to calculate the B-field.
     
  5. Sep 23, 2009 #4

    Born2bwire

    User Avatar
    Science Advisor
    Gold Member

    It is, however, a prime candidate for far-field approximation. If we were to observe the fields at a distance r>>L, then the field should be fairly approximated as a point charge of
    [tex]Q = \int_{-L/2}^{L/2} \rho(z)dz[/tex]
     
  6. Sep 23, 2009 #5

    tiny-tim

    User Avatar
    Science Advisor
    Homework Helper

    oops!

    oops! :blushing:

    I somehow read "finite" as "infinite" :redface:
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook