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y'' - 7y'+ 6y = 2e^(3t) + te^(t)

First i found GS(H) by lettings y = e^(cx)

and got GS(H) = Ae^(6t) + Be^(t)

i then found PS(IH) y'' - 7y'+ 6y = 2e^(3t) by letting y = ae^(3t)

and got PS(IH) = -(1/3)e^(3t)

Now my problem

I am trying to find the other PS(IH) y'' - 7y'+ 6y = te^(t)

do i do this by letting y = (a+bt)e^(t) ??