Generalisation of terms in a series

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The discussion centers on the confusion surrounding the generalization of terms in the Maclaurin series, particularly for the sine function. It clarifies that the variable "r" in the general formula differs from "r" in the sine series expansion, leading to misunderstandings about the corresponding derivatives and terms. Specifically, while the third derivative term should correspond to the seventh term of the series, the odd terms are defined as non-zero, while even terms are zero. The confusion arises from the use of the same variable for different contexts, which misleads the interpretation of the series. Understanding this distinction is crucial for correctly applying the Maclaurin series to functions like sine.
jackiepollock
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Homework Statement
I'm stuck at understanding the generalisation of the terms in a series
Relevant Equations
Maclaurin series
Hello. I'm not sure how the generalisation comes about (where I circle).

I assume that r means the the rth derivative of f(x). If that's the case, as I plug 3 = r into this generalisation, the third derivative term should equal to (-1)^3x^7 /7!, but the third derivative term is -1x^3/3!.

What's the problem?
Screenshot 2021-08-04 at 11.34.27.png


Screenshot 2021-08-04 at 11.45.13.png
 
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##\frac{(-1)^r}{(2r+1)!}x^{2r+1}## is the ##(2r+1)## term of the series, which means that for r=3 you get the ##2r+1=2\cdot 3+1=7## that is the 7th term of the series. The 3rd term of the series is for the ##r'## such that ##2r'+1=3## or ##r'=1##.
In case you wonder what happens to the ##2r## terms of the series, they are all zero because the corresponding derivative at 0 ##f^{(2r)}(0)=0## is equal to zero

Essentially what I am telling you is that the even terms of the series are all zeros and the odd terms are ##\frac{(-1)^r}{(2r+1)!}x^{2r+1}##
 
jackiepollock said:
I assume that r means the the rth derivative of f(x). If that's the case, as I plug 3 = r into this generalisation, the third derivative term should equal to (-1)^3x^7 /7!, but the third derivative term is -1x^3/3!.

What's the problem?
Your assumption is incorrect. The ##r## in the expansion for ##\sin x## and the ##r## in the general formula for the Maclaurin series are different variables. Note in the general formula, the exponent of ##x## is equal to the order of the derivative, so the ##x^7## term is matched to the seventh derivative of ##f##.
 
vela said:
Your assumption is incorrect. The ##r## in the expansion for ##\sin x## and the ##r## in the general formula for the Maclaurin series are different variables. Note in the general formula, the exponent of ##x## is equal to the order of the derivative, so the ##x^7## term is matched to the seventh derivative of ##f##.
Yes I think what confuses him is that the even terms of the series are zero for the specific expansion of ##\sin x## and that they use the same letter r for the generic series formula and for the specific series of sinx.
 

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