- #1
glacier302
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Homework Statement
(a) Let G be a finite group that is divisible by by p^k, and suppose that H is a subgroup of G with order p^j, where j is less than or equal to k. Show that the number of subgroups of G of order p^k that contain H is congruent to 1 modulo p.
(b) Find an example of a finite group that has exactly p+1 Sylow p-subgroups.
Homework Equations
Theorem: Every p-group is contained in a Sylow p-subgroup.
Third Sylow Theorem: Let |G| = p^e*m where p does not divide m. Then the number of Sylow p-subgroups divides m and is congruent to 1 modulo p.
The Attempt at a Solution
I think that I should somehow be using the 3rd Sylow Theorem to prove (a). Also maybe the fact that since H is a p-group, it is contained in a Sylow p-subgroup, and any larger p-group containing H is also contained in a Sylow p-subgroup.
Any help would be much appreciated : )