Get Lorentzian Spherically Symmetric Metric to Sylvester Form

tut_einstein
Messages
31
Reaction score
0
Hi,

I'm trying to determine the exact transformation that brings a spherically symmetric spacetime metric in spherical coordinates to the Sylvester normal form (that is, with just 1 or -1 on its main diagonal, with all other elements equal to zero.) Assuming that the metric has Lorentzian signature, does anyone know how to determine the exact transformation that achieves this?

Thanks.
 
Physics news on Phys.org


This is essentially nothing more than the orthogonal diagonalisation of a symmetric matrix that you probably did loads of times when you first learned about matrices. The coordinate transformation can be calculated from the matrix of eigenvectors. This gives a diagonal matrix, which should have one negative and the rest positive entries. Then you just have to rescale the coordinates to make the entries -1 and +1.
 


henry_m said:
Then you just have to rescale the coordinates to make the entries -1 and +1.

tut_einstein, this, in general, results in a non-holonomic basis. i.e., one that is not induced by any coordinate system. As a specific example, consider Schwarzschild spacetime,

https://www.physicsforums.com/showthread.php?t=102902
 

Similar threads

Replies
17
Views
2K
Replies
8
Views
1K
Replies
8
Views
4K
Replies
7
Views
2K
Replies
1
Views
1K
Replies
3
Views
3K
Back
Top