Getting magnitude and direction of 3 forces

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SUMMARY

The discussion focuses on calculating the magnitude and direction of three coplanar forces: 100 kN at 0 degrees, 70 kN at 120 degrees, and 50 kN at 210 degrees. Using the polygon of forces method, the resultant force was determined to be 42.19 kN at an angle of approximately 58.57 degrees. However, a graphical method indicated a discrepancy in the angle, measuring closer to 75 degrees. The calculations utilized trigonometric functions to resolve the forces into their components.

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anthonyk2013
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I have completed this question but I am not sure I am right.

3 co-planer forces acting at a point 0, 100KN→ at 0deg from o point, 70KN→120deg from o point and 50KN →210deg from o point (hope that make sense, can't draw it).

using a scale of 10mm+10KN determine, By means of polygon of forces method magnitude and direction of their resultant.

force--------Fx=fcosθ------------Fy=sinθ
100KN----100cos0=100 ------100sin0=0
70KN------70cos120=-35 ---- 70sin120=61
50KN------50cos210=-43 ---- 50sin210=-25
-------------------Ʃfx=22 ------------Ʃfy=36

Resultant=42.19KN

Tan-1=o/A=36/22=58.57deg
 
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Looks reasonable to me--except that the units are KN, not N. (You did it using components, but I suppose they wanted you to use a graphical method.)
 
Doc Al said:
Looks reasonable to me--except that the units are KN, not N. (You did it using components, but I suppose they wanted you to use a graphical method.)

When I draw it on graph paper I measured the resultant and it was very close to the one I worked out,
the angle on the other hand is off on the graph it 75deg.
 

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