Given distance and acceleration, find time

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To find the time it takes for a car moving at 50.0 m/s to travel 70.0 m while decelerating, first calculate the acceleration using the formula a = (V_final - V_initial) / Δt, resulting in -8.33 m/s². The appropriate kinematic equation to use is x = 1/2 * a * t² + V₀ * t, which involves both t² and t terms. This leads to a quadratic equation in the form of (stuff)t² + (stuff)t - d = 0. The quadratic formula can then be applied to solve for time. This method effectively addresses the problem of having two 't' variables in the equation.
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Homework Statement


A car is moving at 50.0 m/s and brakes to a halt in 6.00 seconds.
How long does it take the car to travel 70.0 m after the car starts decelerating?


Homework Equations


a=dv/dt
t=??

The Attempt at a Solution


I'm pretty sure I know how to find the acceleration but I'm confused as to how to set up an equation to find the time.
 
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Simple. Use a kinematics equation that has all the variables you need in it. Think about it. You know initial velocity, the distance it travels, and the acceleration. You need to find time. Which formula has all of those variables in it? Let me know if you haven't been given those formulae, and I can give you hints on how to solve it the long way.
The acceleration is simple, remember the basic equation:

a=\frac{V_{Final} - V_{Initial}}{\Delta Time}
 
For the acceleration I got -8.33 m/s2

Then for the time, do I use the equation:
x=1/2*a*t2+Vo*t

When I tried using that equation I was left with two 't' variables and couldn't get it down to one.
 
ScienceGirl90 said:
For the acceleration I got -8.33 m/s2

Then for the time, do I use the equation:
x=1/2*a*t2+Vo*t

When I tried using that equation I was left with two 't' variables and couldn't get it down to one.

Correct formula. However take a look at this, you have d=(stuff)t2+(stuff)t. What kind of function does that look like?
 
It looks like a quadratic function? I don't know how to get it to t='stuff'
 
You don't. You want to get t correct? Well there happens to be this thing called the quadratic formula that will solve for your quadratic variable (t in this case), where the equation is equal to zero.
 
Oh I see! Thank you very much!
 
You're welcome. Let me know how that works out. You should start with:

(stuff)t2+(stuff)t-d=0 and then plug that in.
 

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