Given distance and acceleration, find time

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    Acceleration Time
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Homework Help Overview

The problem involves a car decelerating from an initial speed and requires determining the time taken to travel a specific distance during this deceleration. The subject area pertains to kinematics and motion equations.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of kinematic equations to relate distance, initial velocity, acceleration, and time. There is confusion regarding how to isolate time in the equation, particularly when multiple time variables appear.

Discussion Status

Participants are actively exploring different approaches to set up the equations correctly. Some have provided guidance on using the quadratic formula to solve for time, while others are clarifying the structure of the equations involved.

Contextual Notes

There is an emphasis on understanding the relationships between the variables involved, and participants are questioning the setup of the equations based on the information provided.

ScienceGirl90
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Homework Statement


A car is moving at 50.0 m/s and brakes to a halt in 6.00 seconds.
How long does it take the car to travel 70.0 m after the car starts decelerating?


Homework Equations


a=dv/dt
t=??

The Attempt at a Solution


I'm pretty sure I know how to find the acceleration but I'm confused as to how to set up an equation to find the time.
 
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Simple. Use a kinematics equation that has all the variables you need in it. Think about it. You know initial velocity, the distance it travels, and the acceleration. You need to find time. Which formula has all of those variables in it? Let me know if you haven't been given those formulae, and I can give you hints on how to solve it the long way.
The acceleration is simple, remember the basic equation:

a=\frac{V_{Final} - V_{Initial}}{\Delta Time}
 
For the acceleration I got -8.33 m/s2

Then for the time, do I use the equation:
x=1/2*a*t2+Vo*t

When I tried using that equation I was left with two 't' variables and couldn't get it down to one.
 
ScienceGirl90 said:
For the acceleration I got -8.33 m/s2

Then for the time, do I use the equation:
x=1/2*a*t2+Vo*t

When I tried using that equation I was left with two 't' variables and couldn't get it down to one.

Correct formula. However take a look at this, you have d=(stuff)t2+(stuff)t. What kind of function does that look like?
 
It looks like a quadratic function? I don't know how to get it to t='stuff'
 
You don't. You want to get t correct? Well there happens to be this thing called the quadratic formula that will solve for your quadratic variable (t in this case), where the equation is equal to zero.
 
Oh I see! Thank you very much!
 
You're welcome. Let me know how that works out. You should start with:

(stuff)t2+(stuff)t-d=0 and then plug that in.
 

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