Got wrong from right equations

  • Context: Graduate 
  • Thread starter Thread starter Prasanna Suman
  • Start date Start date
Click For Summary
SUMMARY

The discussion centers on the application of relativistic equations, specifically the Lorentz-Einstein transformation, to derive the correct relationship between length contraction and velocity. The user initially misapplies the equations, leading to an incorrect formulation of length as l = l0 / (1-v^2/c^2)^(1/2). The correct relationship is established as l = l0 * (1-v^2/c^2)^(1/2), emphasizing the importance of consistency when substituting the speed of light (c) into the equations. The conversation highlights the necessity of understanding the relativistic effects on time and length for particles in motion.

PREREQUISITES
  • Understanding of relativistic physics concepts, particularly length contraction.
  • Familiarity with the Lorentz-Einstein transformation equations.
  • Knowledge of the speed of light (c) and its implications in physics.
  • Basic algebra and manipulation of equations involving variables and constants.
NEXT STEPS
  • Study the Lorentz-Einstein transformation in detail to understand its derivation and applications.
  • Explore the implications of length contraction in various relativistic scenarios.
  • Learn about the relationship between time dilation and length contraction in special relativity.
  • Examine case studies involving particles moving at relativistic speeds to see these equations in action.
USEFUL FOR

Students of physics, educators teaching special relativity, and researchers exploring relativistic effects in high-speed particle physics will benefit from this discussion.

Prasanna Suman
Messages
10
Reaction score
0
I got this problem while I was combining relativistic equations:



For particle which is in motion,
v = l /t
or, l = v * t
or, l= v * t0/(1-v^2/c^2)^(1/2) ' Relativistic equation for time "t"

If the particle was light,

l =(c * t0)/(1-v^2/c^2)^(1/2) ' Because velocity of light is always c; c*t0 is equal to l0

or l = l0 / (1-v^2/c^2)^(1/2)

But, the actual relation is l = l0 * (1-v^2/c^2)^(1/2)

I must have been wrong somewhere. Where?
 
Physics news on Phys.org
You should have been consistent when plugging v--->c in your equations.

Daniel.
 
use lorentz-einstein transformation

Prasanna Suman said:
I got this problem while I was combining relativistic equations:



For particle which is in motion,
v = l /t
or, l = v * t
or, l= v * t0/(1-v^2/c^2)^(1/2) ' Relativistic equation for time "t"

If the particle was light,

l =(c * t0)/(1-v^2/c^2)^(1/2) ' Because velocity of light is always c; c*t0 is equal to l0

or l = l0 / (1-v^2/c^2)^(1/2)

But, the actual relation is l = l0 * (1-v^2/c^2)^(1/2)

I must have been wrong somewhere. Where?

Your light signal that starts at t=0 from x=0 generates the event after a time t of propagation (x=ct;t=x/c) in I. The same event detected from I' is (x'=ct';t'=x'/c) and so
l=(x-Vt)/(1-bb)^1/2=l'((1+b)/(1-b))
with b=V/c.
the best things a physicist can offer to another one are information and constructive criticism
 

Similar threads

  • · Replies 32 ·
2
Replies
32
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 15 ·
Replies
15
Views
1K
  • · Replies 9 ·
Replies
9
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 31 ·
2
Replies
31
Views
3K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K