GRADE 12: Energy, Springs and maybe momentum/collisions?

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SUMMARY

The discussion focuses on deriving an equation to calculate the distance a spring must be pulled back to hit a target, given specific parameters such as mass (m), launch angle (θ), vertical distance (dy), horizontal distance (dx), and spring constant (k). Key equations include the conservation of mechanical energy (Ei = Ef) and the kinetic energy formula (Ek = 1/2 MV^2). The problem also requires understanding 2D projectile motion, particularly when initial and final heights differ. The example provided illustrates a scenario with a spring mass of 4.5 g, a launch angle of 30 degrees, and a target height of 0.40 m.

PREREQUISITES
  • Understanding of 2D trajectory equations
  • Knowledge of conservation of mechanical energy principles
  • Familiarity with kinetic energy calculations (Ek = 1/2 MV^2)
  • Comprehension of spring potential energy (Ee = 1/2 KX^2)
NEXT STEPS
  • Study the SUVAT equations for constant acceleration
  • Research projectile motion with varying initial and final heights
  • Explore the relationship between spring constant (k) and displacement (x)
  • Practice problems involving energy conservation in spring systems
USEFUL FOR

Students in physics, particularly those studying mechanics, as well as educators looking for examples of energy conservation and projectile motion applications.

michael simone
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Homework Statement


A spring of mass “m” is put on a launcher elevated at “θ” degrees above the horizontal. It is pull back a distance “x” and launched at a target that must travel vertically “dy“ and a horizontal distance of “dx”. The spring has a constant of “k”.Derive an equation (or series of equations) given m, θ, dy ,dx, k so you can calculate a value of x.Example The target is 3.5 m away and the launder is elevated at 30o and it is 1.2 m high, the mass of the spring is 4.5 g, what distance should the spring be pulled back to land in a target that is 0.40 m tall if k = 18 N/m?

Homework Equations


PTi= PTf
Ei=Ef
ENERGY
KINETIC (Ek)
Ek=1/2 MV^2
SPRINGS(elastic Ee)
Ee=1/2 KX^2
E1=E2 IE
Potential (Eg)
Eg= mgh or mg(delta y)
vx= vicos (theta)
Projectile motion and Energy[/B]

The Attempt at a Solution

 
Last edited:
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Check your textbook for 1) 2D trajectory equations and 2) the conservation of mechanical energy. You will need both.
 
Dr Dr news said:
Check your textbook for 1) 2D trajectory equations and 2) the conservation of mechanical energy. You will need both.
ENERGY
KINETIC (Ek)
1/2 MV^2
SPRINGS(elastic Ee)
1/2 KX^2
E1=E2 IE
Potential (Eg)
mgh or mg(delta y)
vx= vicos (theta)
 
The classical range equation is based on the initial elevation and the final elevation both being on the ground. In your problem you have an initial height as well as a final height which means you need to carry them along in your trajectory analysis.
 
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thanks for that tip, but how do i slove this when v is not provided.
 

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