Grandfather clock torque homework

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SUMMARY

The discussion centers on calculating the torque exerted by a 55 g mouse at the end of a 17 cm long grandfather clock hand when the clock reads 10 minutes past the hour. The torque is calculated using the formula Torque = rFsin(theta), where the force (F) is determined to be 0.55 N based on the mouse's weight. The angle (theta) is established as 60 degrees, resulting from the 30-degree position of the clock hand and the 90-degree angle of the force. The reasoning provided is confirmed as sound by participants in the discussion.

PREREQUISITES
  • Understanding of torque and its calculation
  • Knowledge of basic physics concepts such as force and weight
  • Familiarity with trigonometric functions, specifically sine
  • Ability to convert units, particularly grams to newtons
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  • Study the principles of rotational dynamics and torque calculations
  • Learn about the applications of torque in mechanical systems
  • Explore trigonometric identities and their use in physics problems
  • Investigate the effects of varying angles on torque in different scenarios
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This discussion is beneficial for physics students, educators, and anyone interested in understanding torque calculations in mechanical systems, particularly in relation to rotational motion.

mvl46566
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Homework Statement


A 55 g mouse runs out to the end of the 17cm long hand of an old grandfather clock when the clock reads 10min past the hour. What torque does the mouse exert about the rotation axis of the clock hand.


Homework Equations



Torque=rFsin(theta)

The Attempt at a Solution



The force acting on the mouse is his weight, so F=mg which turns out to be .55N. The radius, in meters, is .17m. Here's the tricky part, theta describes the angle between the force and the radius, so, if it is 10 past the hour, the long hand is making a 30 degree angle with the x-axis (or the 3 on a clock). The force, long hand, and x-axis make a 90 degree angle so if the angle the long hand makes with the axis is 30 degrees and the angle force makes with the axis is 90 degrees then theta must equal 60 degrees.

That is my logic but I am not sure how sound it is. If anyone can help confirm or deny this it would be much appreciated!
 
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Yup, your reasoning is sound.
 

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