Graph & Analyze Fourier Coefficient of Periodic Function

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longball
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A periodic function f(x) has period 2 and is defined as

f(x) = -2.4 (x+1) ,-1 ≤ x < 0
2.4 (1-x) , 0 < x ≤ 1

with f(x+2) = f(x) for all x

sketch the graph of f(x) over the interval (-4, +4) and determine the Fourier coefficient Ao.

I really don't know where to start with this question any help would be great.
 
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no i don't know where to start with the graph. I am guessing that the graph is to take the shape of a saw tooth, could be wrong though. i also do not understand what the (x+1) (x-1) stands for
 
start with the first part of the graph
f(x) = -2.4 (x+1) ,-1 ≤ x < 0

multiplying out the brackets gives
f(x) = (-2.4)*x - 2.4
this is the equation of a straight line, can you plot it on the x interval from -1 to 0?

do similar for
f(x) = (-2.4)*x + 2.4
and plot it for on the x interval from 0 to 1