Graph of a trigonometric function

  • Thread starter Duane
  • Start date
  • #1
8
0
How do you graph f'(x) when f(x)= sin(x+sin2x), 0≤x≤∏ ?

If I calculate f'(x) first by the chain rule, I get f'(x)=cos(x+sin2x)(1+cos2x), where to proceed ?

Thanks for any help in advance.
 

Answers and Replies

  • #2
998
15
How do you graph f'(x) when f(x)= sin(x+sin2x), 0≤x≤∏ ?

If I calculate f'(x) first by the chain rule, I get f'(x)=cos(x+sin2x)(1+cos2x), where to proceed ?

Thanks for any help in advance.

Do not forget the '2'.

f'(x)=(1+2cos2x)cos(x+sin2x)
 
Last edited:

Related Threads on Graph of a trigonometric function

  • Last Post
Replies
2
Views
3K
  • Last Post
Replies
7
Views
4K
  • Last Post
Replies
3
Views
2K
Replies
4
Views
2K
  • Last Post
Replies
10
Views
11K
  • Last Post
Replies
7
Views
3K
Replies
2
Views
3K
Top