- #1

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If I calculate f'(x) first by the chain rule, I get f'(x)=cos(x+sin2x)(1+cos2x), where to proceed ?

Thanks for any help in advance.

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- Thread starter Duane
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- #1

- 8

- 0

If I calculate f'(x) first by the chain rule, I get f'(x)=cos(x+sin2x)(1+cos2x), where to proceed ?

Thanks for any help in advance.

- #2

- 998

- 15

If I calculate f'(x) first by the chain rule, I get f'(x)=cos(x+sin2x)(1+cos2x), where to proceed ?

Thanks for any help in advance.

Do not forget the '2'.

f'(x)=(1+

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