Graph of Voltage vs Length for Moving Rod in Magnetic Field

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SUMMARY

The discussion focuses on the relationship between the induced voltage and the motion of a rod in a magnetic field, specifically using the equation EMF = -v*B*L. As the rod moves with a constant velocity v through a magnetic field of strength B, the induced voltage remains constant, resulting in a horizontal line on the graph of voltage versus length. This indicates that the voltage does not change with the length of the rod when moving at a constant speed, contrary to the initial assumption of a varying slope.

PREREQUISITES
  • Understanding of electromagnetic induction principles
  • Familiarity with the equation for induced EMF
  • Basic knowledge of graphing functions
  • Concept of magnetic fields and their effects on moving charges
NEXT STEPS
  • Study the principles of Faraday's Law of Electromagnetic Induction
  • Learn about the effects of varying magnetic fields on induced voltage
  • Explore the concept of Lorentz force in relation to moving charges
  • Investigate practical applications of induced EMF in electrical engineering
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Students studying electromagnetism, physics educators, and electrical engineering professionals interested in the principles of electromagnetic induction and their applications.

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Homework Statement



Here is the problem:

Given a rod of Length L with one end centered at the origin and the other at y=L and given a magnetic field of strength B that points out of the page, what is the graph of the magnitude of the voltage read by a voltmeter as a constant velocity is applied to the rod as it moves across the field?



Homework Equations



E_y, Induced = -v *B (electric field induced)
EMF = -v*B*L



The Attempt at a Solution




I am having trouble visualizing the specifics of the motion, if it is a constant velocity should i expect a constant slope for the graph of the voltage with traits similar to X=Y or is it simply a constant value? (which seems unreasonable)
 
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Can't you use this equation to derive the answer? ;-).

"EMF(voltage) = -v*B*L"
 

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