I Grating Resolving Power of Laser Beams with Gaussian Distribution

AI Thread Summary
Grating resolving power calculations typically assume a uniform distribution, leading to airy disks based on the Rayleigh criterion. For Gaussian laser beams, the standard resolvance definition may not apply, as it relies on uniformity. The formula for resolving power, R = λ/Δλ = mN, where m is the order and N is the number of illuminated slits, remains straightforward without incorporating the beam's width. Introducing a function of the 1/e^2 width (wo) complicates the resolution estimation unnecessarily. Ultimately, the resolving power for a truncated Gaussian beam is expected to decrease compared to that of a uniform beam.
mikey1234
Messages
1
Reaction score
0
TL;DR Summary
Grating resolving power for Gaussian Beams vs Uniform incidence
All resources I’ve found for grating resolving power assume uniform distribution on the grating and produce airy disks. Resolvance is determined by the Rayleigh criterion where the peak of one wavelength is at the minima of the adjacent one. This definition doesn’t seem applicable for Gaussian laser beams.

How does the grating resolving power of Lamda/(delta Lambda) = mN, where m is the order (assume 1) and N is the number of slits illuminated change for a diffraction limited laser beam with a Gaussian distribution? Let’s say our criterion for resolvance is separating the peaks by wo (1/e^2 width) diameter.
 
Science news on Phys.org
The resolution formula is used to estimate the resolution of a diffraction grating spectrometer, and there is very little to be gained by trying to do the calculation for a beam with a Gaussian distribution. The resolving power ## R=\frac{\lambda}{ \Delta \lambda}=N m ## is a nice simple one, and it would unnecessarily complicate matters to have some function of ## w_o ## in this formula.
 
The resolution power for truncated Gaussian beam would only decrease compare to the uniform beam.
 
Hello ! As we know by definition that: "Constructive interference occurs when the phase difference between the waves is an even multiple of π (180°), whereas destructive interference occurs when the difference is an odd multiple of π." But my question is in the case of destructive interference, what happens to the energy carried by the two electromagnetic waves that annihilate, the energy carried by the electromagnetic waves also disappears, or is transformed into some other type of...
I am currently undertaking a research internship where I am modelling the heating of silicon wafers with a 515 nm femtosecond laser. In order to increase the absorption of the laser into the oxide layer on top of the wafer it was suggested we use gold nanoparticles. I was tasked with modelling the optical properties of a 5nm gold nanoparticle, in particular the absorption cross section, using COMSOL Multiphysics. My model seems to be getting correct values for the absorption coefficient and...
Back
Top