- #1
- 33
- 0
Maybe someone can help with this question:
How to calculate as possible precisely gravitational acceleration (g) at Mariana Trench?
How to calculate as possible precisely gravitational acceleration (g) at Mariana Trench?
You are assuming spherical gravity here. The OP asked for a calculation as precise as possible.mg=GMm/(r*r)
you can easily find it yourself, if you choose a particular place: the deepest spot [discovered in 2009] is 10,971 m closer to Earth's center than see level, if you are looking for max g, [as Earth is not a perfect sphere] some parts of the Arctic Ocean are 13,000 m closer then Marianas.... precisely gravitational acceleration (g) at Mariana Trench?
That's the Preliminary Reference Earth Model, see http://geophysics.ou.edu/solid_earth/prem.html [Broken]. That model is not going to help you much if you really do want a precise number.I found a plot of density and g here:
http://members.arstechnica.com/x/bravehamster/gravity.GIF [Broken]
The GOCE data are still preliminary, but you can find some space-only spherical harmonics models based on GOCE, GRACE, CHAMP, and SLR. The GOCO02S model coefficients are at http://ftp.tugraz.at/pub/goco/GOCO02S/GOCO02S.gfc. To use these, you are going to have to find the geoid at your target location. That alone is going to be a bit tough; those deep sea trenches are places where the geoid height varies a lot. You can find software to help with this process on the web. Now that you have the geoid you can assume that mean sea level is the geoid. So now you can get g by applying the spherical harmonics. Since this is a space-only solution, you are going to have to add in the centrifugal acceleration at that point. (g includes acceleration due to gravity and centrifugal acceleration).g on a surface of the Earth likely can be find from Goce data
http://www.bbc.co.uk/news/science-environment-12911806
you simply ought to find out what is g at the latitude you choose.
you are going to have to add in the centrifugal acceleration at that point.[PLAIN]http://www.uklv.info/g.php[/QUOTE] [Broken]
if one gets precise value of g at that place, isn't it inclusive of all factors?
When I said "add" I mean vector sum. Gravitation is directed inward, more or less toward the center of the Earth, centrifugal force is directed outward, away from the Earth's rotation axis. In physical geodesy, gravity and gravitation are two different things. Gravitation is the inward acceleration described by Newton's law of gravitation. Gravity is the vector sum of the gravitational and centrifugal accelerations.you are going to have to add in the centrifugal acceleration at that point.
1) what is the order of precision you would like to achieve?, if precise g at sea level is available, ordinary formula won't satisfy you?1) As I see here may be too much factors to get real numbers.
2) But let's consider we want practically to measure g by immersing some probe.
Lets say this probe has construction possibilities to come out later.
1)What types of g-meters inside this probe would be able to measure most accurate results?
MIMS accelerometers with sensitivities on the order of a hundred milligals are a dime a dozen; you might well have one in your cellphone. Custom inertial measurement units with sensitivities on the order of a milligal are used in airplanes, spacecraft , ships, and submarines. Superconducting gravimeters with sensitivities on the order of a nanogal have been built, but you are not going to be able to put such a device in your hypothetical probe.As I see here may be too much factors to get real numbers.
But let's consider we want practically to measure g by immersing some probe.
Lets say this probe has construction possibilities to come out later.
What types of g-meters inside this probe would be able to measure most accurate results?
Maybe someone can help with this question:
How to calculate as possible precisely gravitational acceleration (g) at Mariana Trench?
What are you rambling on about?
I think that, not for the first time, the deluge of answers just didn't match such a vague original question.
people deliberately ask vague nonsense questions,... just to sit back and watch the posts fly. :rofl:
OP is in good faith, and he showed it*, [probably ] he needs an accuracy greater than 10-7, he would like to realize experiment after 20 years, and he hopes to make a great discovery. Good luck to him!I just need some realistic points for realistic experiments where Θ and Φ differs maximally.
... experiment was proposed *http://www.sciencedirect.com/science/article/pii/037596019190554L...But ... still was not done.