Gravitational force & escape velocity

AI Thread Summary
The gravitational force is described by the equation F = mk/r^2, where the negative value of k indicates that gravity is an attractive force acting in the negative radial direction. For escape velocity, the initial velocity can be derived as v(initial) = √(2gR), which can be proven using the principle of conservation of energy. This relationship shows that the kinetic energy required to escape a gravitational field is equal to the gravitational potential energy at that distance. Understanding these concepts is crucial for grasping the fundamentals of gravitational interactions and escape dynamics. The discussion emphasizes the mathematical foundations of gravitational force and escape velocity.
hadeel
Messages
5
Reaction score
0
1- F = mk/r^2 ... k is -ve value ...why ?? please in concise way


2- for escape velocity ...
v( inital) = root ( 2gR )... with proof

thank u
 
Physics news on Phys.org
hadeel said:
1- F = mk/r^2 ... k is -ve value ...why ?? please in concise way
Gravity is an attractive force, which acts in the -r direction.

2- for escape velocity ...
v( inital) = root ( 2gR )... with proof
Prove it for yourself using conservation of energy.
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Thread 'Beam on an inclined plane'
Hello! I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below. Here is how I wrote the condition of equilibrium forces: $$ \begin{cases} F_{g\parallel}=F_{t1}+F_{t2}, \\ F_{g\perp}=F_{r1}+F_{r2} \end{cases}. $$ On the other hand...
Back
Top