Group Homomorphism: Prove Existence of Element a

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Homework Help Overview

The problem involves a group G and a map ф from G to G, with a specific condition relating to the products of elements in G. The goal is to prove the existence of an element a in G such that a new map defined by @(x) = a ф(x) is a homomorphism.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the definition of the element a and its role in the map @(x). There is uncertainty about the nature of ф and whether it can be assumed to be a homomorphism. Some suggest using the identity element to derive properties of the map.

Discussion Status

Participants are exploring the implications of the conditions given in the problem. Some guidance has been offered regarding the relationship between the identity element and the map @(x). There is an ongoing examination of the properties of ф and how they relate to the construction of a homomorphism.

Contextual Notes

There is a noted ambiguity regarding the nature of ф, as participants question whether it can be treated as a homomorphism. The discussion includes attempts to clarify the definitions and roles of the elements involved.

nadineM
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Homework Statement


Let G be a group with identity e and product ab for any elements a and b of G.
Let ф: G⟶G be a map such that Ф(a sub1)ф (a sub2)ф(a sub3) = ф(b sub1) ф(b sub2) ф(b sub3) whenever,
(a1) (a2)(a3) = e=(b1) (b2) (b3) for any(not necessarily distinct) elements a1 ,a2 ,a3, b1, b2, b3 of G.
Prove: There exists an element a in G such that the map @: G⟶G defined by @(x) = a ф(x) for every element x in G, is a homomorphism.

Homework Equations


Def: A homommorphism Ф from a group G to a group G is a mapping from G to G that preserves the group opperation. That is, Ф(ab) = Ф(a)Ф(b) for all a, b in G
Properties of elements under a homomorphism:
Ф carries the identity in G to the identity in G
Ф preserves inverses
*note that the Ф in this section is not the same as in the question...

The Attempt at a Solution



I really haven't got a clue on where to even begin to define "a" I am thinking that it needs to be triplet for example aea^(-1)...but I have no idea what to do or where to start...I am completely lost, can anyone give me a push in the right direction?:confused:
 
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Combine the facts "homomorphisms carry the identity in G to the identity in G" with "@(x) = aф(x)" to determine a.
 
I don't have a homomorphism though... I am not given the fact that Ф is a homomorphism?
 
AKG's point is that '@' is supposed to be a homomorphism, not the original function. So @(e) had better be e. Can we change symbols here?
 
Dick said:
AKG's point is that '@' is supposed to be a homomorphism, not the original function. So @(e) had better be e. Can we change symbols here?

OK thanks...I will work with that for a bit and see where I get...you can use what ever symbol you like i tried using gamma but couldn't get it to come up right...
 
It might help to experiment with ф to try and understand it better.

You have an identity it satisfies -- try plugging special values into those identities to see if you can deduce other facts about ф.

Try choosing a group and constructing an actual function ф that satisfies the listed properties.
 

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