Group of order 100 with no element of order 4?

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Homework Help Overview

The discussion revolves around the existence of a group of order 100 that contains no elements of order 4. Participants are exploring group theory concepts, particularly in relation to direct products and their implications for group structure.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the potential construction of a group using direct products, specifically considering the structure \(\mathbb{Z}_{5}\times\mathbb{Z}_{5}\times\mathbb{Z}_{2}\times\mathbb{Z}_{2}\). There is an inquiry into whether this construction meets the criteria of having no elements of order 4.

Discussion Status

The conversation is ongoing, with participants sharing ideas about group construction. There is a suggestion that a specific direct product could serve as a solution, but no consensus has been reached regarding its validity or completeness.

Contextual Notes

Participants are operating under the assumption that the group must adhere to certain properties related to its order and the orders of its elements, as indicated by the initial problem statement.

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1. Homework Statement [/]
Is there a group G with order 100 such that it has no element of order 4? How would one go about proving the existence of such a group?



2. Homework Equations [/]
For every prime divisor p of a group, there exists an element with order p.



The Attempt at a Solution

 
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Do you know about direct products? If so, you should be able to construct such a group pretty easily.
 
Yes I do have some knowledge of direct products. Could I construct a group as such: [tex]\mathbb{Z}_{5}\times\mathbb{Z}_{5}\times\mathbb{Z}_{2}\times\mathbb{Z}_{2}[/tex]?
 
kpoltorak said:
Yes I do have some knowledge of direct products. Could I construct a group as such: [tex]\mathbb{Z}_{5}\times\mathbb{Z}_{5}\times\mathbb{Z}_{2}\times\mathbb{Z}_{2}[/tex]?

That's the one I had in mind.
 

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