Okay, I'm really scratching my head here.(adsbygoogle = window.adsbygoogle || []).push({});

If an Abelian group A has three generators x,y,z and they are subject to three defining relations, say something like

x+y+z=0

x-y-z=0

2x-2y+3z=0

then I can solve for x,y,z and find A as a direct sum of cyclic groups, Z_x + Z_y + Z_z.

But what do I do if the three equations are not linearly independent? I get left with everything in terms of x and I can't just plug in the numbers.

Thanks,

N.

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# Groups. I am stumped again.

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