Hai Calculating Net Electrostatic Force Need help :(

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Homework Help Overview

The discussion revolves around calculating the net electrostatic force acting on a charged object (-5 µC) due to other nearby charged objects. Participants are exploring the principles of electrostatics and vector addition in the context of forces between charged particles.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss calculating individual forces acting on the charged object and determining their nature (attractive or repulsive). There are attempts to apply trigonometry to find the resultant force vector. Some participants express uncertainty about their calculations and seek clarification on vector components and the use of the cosine rule.

Discussion Status

The discussion includes various attempts to calculate the forces and their resultant vector. Some participants have provided guidance on constructing vector triangles and using trigonometric functions, while others have raised questions about the assumptions made in the calculations. There is no explicit consensus on the correct approach or final answer, as multiple interpretations and methods are being explored.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the information they can share or the methods they can use. There are indications of potential errors in unit conversions and assumptions about angles in vector calculations.

Mori
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Homework Statement


Three charged objects are placed as shown. Find the net force on the object with the charge of -5uC
Diagram:[/B]
http://imgur.com/xHGHGbd

Homework Equations


No idea what to do as far as steps go, I don't know how to start :([/B]

The Attempt at a Solution


None so far.
 
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Try calculating the magnitude of the forces (individually) acting on the specified object and determine their nature (i.e. attractive/repulsive) , then find the resultant vector of force using trigonometry.
 
Okay, I'll go find each one acting on it, gimme a sec :D
 
6uc vs. -5uc = -0.0902135052958669(Attractive)
-7uc vs. -5uc = 0.07875 N(Repulsive)

How do I use these in trigonometry?
 
You've made a unit conversion error somewhere - it should be 9.023...N and 7.875 N.
 
Oh, sorry xD
I might've typed it wrong,or I'm just kinda dumb.
 
The forces will be vectors, so construct a vector triangle and find the "length of the missing side" in terms of Newtons.
 
Not true - even PhD students can make conversion errors.
 
I got 34.6456i, 36.68 deg. S of E, did I get it? :D
 
  • #10
I'm afraid that is incorrect; how can the force have a magnitude which is non-real in this case? I suggest that you use the cosine rule to find the resultant force.
 
  • #11
I did these, what did I do wrong?
Multiply it by sin(30) and multiply 7.875 again by cos(30) = (6.82 N, 3.94 N)
Turn the 6uc into vector components. = (-9.02 N,0)
Add the two vectors = (-2.2, 3.94)
Use pythagorean theorem on it = 3.27 N
Arctangent to find direction= -60.809688481761 degrees
3.37 N, 60 degrees N of W
 
  • #12
The vector triangle will not be right angled - do you have a justification for assuming one of the angles between the vectors to be 90 degrees? The resultant won't be on the same line as the 10cm one, so using pythagoras' principle won't work. Try using the cosine rule.
 
  • #13
4.68 N, 57.4deg S of E
Got that after various tries, done?
 
  • #14
Multiply it by sin(30) and multiply 7.88 again by cos(30) = (6.82 N, -3.94 N)
Turn the 6uc into vector components. = (-9.34 N,0)
Add the two vectors = (-2.52, 3.94)
Use pythagorean theorem on it = 4.68 N
Arctangent to find direction= -57.4 Degrees
4.68 N, 57.4deg S of E
 

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