Halliday, Resnick & Krane Chapter 5: Force on Pulley

AI Thread Summary
To solve for the tension in the pulley system, the equations for both masses m1 and m2 are established, showing that the force on the pulley equals twice the tension. The equations are combined to express tension in terms of acceleration and gravitational force. A question arises about the definition of acceleration and whether both masses experience the same acceleration. Clarification on these points is needed to proceed with the solution. Understanding the relationship between the masses and their acceleration is crucial for solving the problem effectively.
vibha_ganji
Messages
19
Reaction score
6
Homework Statement
Someone exerts a force F directly up on the axle of the pulley shown in Fig. 5-45. Consider the pulley and string to be massless and the bearing frictionless. Two objects, m1 of mass 1.2 kg and m2 of mass 1.9 kg, are attached as shown to the opposite ends of the string, which passes over the pulley. The object m2 is in contact with the floor. (a) What is the largest value the force FB may have so that m2 will remain at rest on the floor? (b) What is the tension in the string if the upward force F is 110 N? (c) With the tension determined in part (b), what is the acceleration of m1?
Relevant Equations
F=ma
Force on pulley = 2(tension)
As the force on a pulley is equal to twice the tension, I just have to find the tension to solve part A. To do so, I first wrote the equations for both m1 and m2.

m1 * a = T - m1g

m2 * a = T + N - m2g

The tension must have the same values for both equations so I added both equations to find the tension.

m1a + m2a = 2T + N - g(m1 + m2)
a(m1+m2) + g(m1+m2) = 2T + N

(a+g)(m1+m2) - N = 2T

I’m not sure what to do next. Can I have a hint?
F3E23044-B23C-487C-A296-375AD1023D15.jpeg
 
Last edited:
Physics news on Phys.org
vibha_ganji said:
m1 * a = T - m1g

m2 * a = T + N - m2g
How are you defining a? Will the masses have the same acceleration?
 
Thread 'Minimum mass of a block'
Here we know that if block B is going to move up or just be at the verge of moving up ##Mg \sin \theta ## will act downwards and maximum static friction will act downwards ## \mu Mg \cos \theta ## Now what im confused by is how will we know " how quickly" block B reaches its maximum static friction value without any numbers, the suggested solution says that when block A is at its maximum extension, then block B will start to move up but with a certain set of values couldn't block A reach...
TL;DR Summary: Find Electric field due to charges between 2 parallel infinite planes using Gauss law at any point Here's the diagram. We have a uniform p (rho) density of charges between 2 infinite planes in the cartesian coordinates system. I used a cube of thickness a that spans from z=-a/2 to z=a/2 as a Gaussian surface, each side of the cube has area A. I know that the field depends only on z since there is translational invariance in x and y directions because the planes are...

Similar threads

Back
Top