- #1

IamVector

- 98

- 9

- Homework Statement
- A block is pushed onto a conveyor belt. The belt

is moving at velocity v0 = 1 m/s, the block’s initial velocity

u0 = 2 m/s is perpendicular to the belt’s velocity. During its

subsequent motion, what is the minimum velocity of the block

with respect to the ground? The coefficient of friction is large

enough to prevent the block from falling off the belt.

- Relevant Equations
- hint given : we use the conveyor’s frame, but

as we are asked about the speed in lab frame, we need

to switch back to the lab frame. In the conveyor’s frame,

the velocity vector becomes shorter while preserving the

direction, i.e. can be represented as ⃗w = k ⃗w0, where its

initial value ⃗w0 = ⃗v0 −⃗u0 and the factor k takes numerical

values from 0 to 1. Hence, the velocity in the lab frame

⃗v = ⃗u0 + k ⃗w0: this is a vector connecting the right angle

of the right triangle defined by its catheti ⃗u0 and ⃗v0 with a

point on the hypotenuse; the specific position of this point

depends on the value of the factor k (which is a function

of time).

stuck on this question