Harmonic Motion-Just need to make sure

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SUMMARY

A mass of 100 g suspended from a spring exhibits simple harmonic motion with a period of 0.993 seconds. The spring constant (k) can be calculated using the formula k = (4π²m) / T². Substituting the mass (0.1 kg) and the period (0.993 s) into the equation yields a spring constant of approximately 0.637 N/m. This calculation confirms the relationship between mass, period, and spring constant in harmonic motion.

PREREQUISITES
  • Understanding of simple harmonic motion principles
  • Familiarity with the formula T = 2π(m/k)^(1/2)
  • Basic knowledge of mass and spring systems
  • Ability to perform unit conversions (grams to kilograms)
NEXT STEPS
  • Study the derivation of the formula for the period of a spring-mass system
  • Explore the effects of varying mass on the spring constant
  • Learn about energy conservation in simple harmonic motion
  • Investigate real-world applications of harmonic motion in engineering
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Students studying physics, particularly those focusing on mechanics and harmonic motion, as well as educators looking for examples of spring-mass systems in action.

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Homework Statement


A mass of 100 g is hanging from a spring and is set into simple harmonic motion. If the period of the pendulum is 0.993 s, what is the spring constant?



Homework Equations



T=2pi(m/k)1/2

The Attempt at a Solution


I just want to make sure its right before I plug in the answer. Thanks.

T^2 = 2pi *(m/k)

k*T^2 = 2pi * m

k = (2pi*m)/T^2 = .637 N
 
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T^2 = 2pi *(m/k)

T^2 = 4(pi)^2*(m/k)
 
rl.bhat said:
T^2 = 2pi *(m/k)

T^2 = 4(pi)^2*(m/k)
kk, thanks. :)
 

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