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OK. Good luck with your model.
bapowell said:What do your symbols mean?
StateOfTheEqn said:I'm rejecting all the Friedmann solutions because they all depend on p=0.
The following are equivalent:twofish-quant said:No they don't.
There is no discarding or modification of the equations of GR nor any new theory of gravity. The equation of state in (3) does require a default value of (density)diag(1,-1/3,-1/3,-1/3) for the energy-momentum tensor but (density) is so small that the modification would not appreciably affect the gravitational fields of gravitating bodies. So, I would not call it a significant modification of the GR field equations. It is certainly less of a modification than adding a cosmological constant.twofish-quant said:What you do is to take the FRW equation, put in your favorite expression for P, and then you get expansion rates. Or you go backward and put in observed expansion rates, and that will give you P.
You can do this with your equation for P, and I am 99% certain that you'll get expansion rates that look nothing like what the universe looks like.
You can fix this by tossing FRW and coming up with a new theory of gravity. People *have* been doing this, and there are hundreds maybe thousands of papers that try to explain observations by assuming new gravity. The general technique is to use an f(R) model in which they new theory of gravity is like GR for short distances (since we can see how gravity behaves at short distances) but different for long distances.
That may be true but there is one thing to consider. Any interpretation of data involves assumptions, especially in cosmology. I think the theory I am proposing explains the redshift anomaly without resorting to 'dark energy'. I have tried to follow Occam's Razor - do not add unnecessary entities! I have proposed a theory that has no parameters but from which you can derive the Hubble Relation.twofish-quant said:The problem with what you are doing is that if you start with a specific theory about what is causing the universe to expand and you work through the numbers, you end up with something that looks nothing at all like the universe.
twofish-quant said:What people are doing is starting with the observations, then working out what *could* cause those observations, and then hopefully we will be able to pin down, what it is or isn't.
It's actually a fun thing to do. If you want to join in on the hunt, we could use people. But people have tried what you are doing, and it hasn't worked, and if you aren't willing to listen to why it doesn't work, then I don't know what to do.
StateOfTheEqn said:The following are equivalent:
1) p=0
2) M=constant.
3) The Friedmann equation holds true.
The proof is in Semi-Riemannian Geometry by Barrett O'Neill (1983) p.351
6)How do we decide among them? We look at the R-W metric and ask whether there is a canonical (natural) constant rate of expansion associated with that metric. There is. Set dR^2=c^2dt^2. That gives us R=ct where R is to be considered the length of the past world-line of an observer.
That may be true but there is one thing to consider. Any interpretation of data involves assumptions, especially in cosmology. I think the theory I am proposing explains the redshift anomaly without resorting to 'dark energy'.
I have tried to follow Occam's Razor - do not add unnecessary entities!
I have proposed a theory that has no parameters but from which you can derive the Hubble Relation.
I admit it does require reinterpreting redshift somewhat. Instead of v=cz , I have v=cz/(z+1) and D=cz/H(z+1).
It's been fun and I'll leave you with the last word.
Yeah, that's wrong.The following are equivalent:
1) p=0
2) M=constant.
3) The Friedmann equation holds true.
The proof is in Semi-Riemannian Geometry by Barrett O'Neill (1983) p.351
Yes, this.twofish-quant said:If you can get the graphs to match without any parameters at all, that would be amazing, but I think you will have to add some parameters.
I strongly advise that you work through a cosmology textbook and derive the Friedmann Equations from the Einstein Equations. You will see that the Einstein Equations reduce to the Friedmann Equations given two assumptions: homogeneity and isotropy. If you believe that the universe is homogeneous and isotropic, and if you start with GR, then you must end up with the Friedmann Equations.StateOfTheEqn said:1)Is the p=0 assumption in the three Friedmann models necessary?
Instead of v=cz , I have v=cz/(z+1) and D=cz/H(z+1).
twofish-quant said:I'll have to take a look at his book, but if he says that then he is wrong (and yes textbooks can be wrong).
StateOfTheEqn said:The following are equivalent:
1) p=0
2) M=constant.
3) The Friedmann equation holds true.
The proof is in Semi-Riemannian Geometry by Barrett O'Neill (1983) p.351
O'Neill said:Lemma. Let [itex]M(k,a)[/itex] be a Robertson-Walker spacetime with [itex]a[/itex] nonconstant. Then the following are equilvalent:
(1) The perfect fluid [itex]U[/itex] is a dust.
(2) [itex]\rho a^3 = m[/itex], a positive constant.
(3) (Friedmann-equation) [itex]a'^2 + k = A/a[/itex], where [itex]A = 8 \pi m/3 > 0[/itex].
George Jones said:This is correct.
Where is the center of rotation? The universe is highly homogeneous and isotropic on large scales -- we simply don't see what you're describing.leonstavros said:Why can't we assume that the universe is expanding due to centrifugal forces from a spinning universe. If we assume an hour-glass universe with one-half of it being a black hole and the other half connected with our "universe" but still part of the same hour-glass universe. As the black hole spins so does the other half(us). If the black hole universe starts feeding,it will speed up by the extra mass and therefore speed up the rate of spin on our half of the universe. As the rate of spin increases the centrifugal force increases making all the galaxies recede faster from each other.
bapowell said:Where is the center of rotation? The universe is highly homogeneous and isotropic on large scales -- we simply don't see what you're describing.
leonstavros said:Why can't we assume that the universe is expanding due to centrifugal forces from a spinning universe.
If we assume an hour-glass universe with one-half of it being a black hole and the other half connected with our "universe" but still part of the same hour-glass universe. As the black hole spins so does the other half(us). If the black hole universe starts feeding,it will speed up by the extra mass and therefore speed up the rate of spin on our half of the universe. As the rate of spin increases the centrifugal force increases making all the galaxies recede faster from each other.
The Big Bang did not occur at a single location -- it was not an isolated "explosion" occurring within an already existing space. See Marcus's Sticky note on the balloon analogy to get a better understanding of how the Big Bang is viewed.leonstavros said:The center would be the same place where the Big Bang occurred.
bapowell said:The Big Bang did not occur at a single location -- it was not an isolated "explosion" occurring within an already existing space. See Marcus's Sticky note on the balloon analogy to get a better understanding of how the Big Bang is viewed.
The age can be approximately inferred from the present expansion rate,leonstavros said:I'm confused, how then do we know how old the universe is? Don't cosmologists extrapolated the age and the center of the universe from galaxies receding at a certain direction and velocity?
twofish-quant said:It is correct because O' Neill defines what he is calling the Friedmann equation. However, what O'Neill calls the Friedmann equation in that paragraph is not what cosmologists normal use for the term.
see http://en.wikipedia.org/wiki/Friedmann_equations
It's a different equation that includes pressure terms.
George Jones said:I think that the problem is one of terminology. I think that Friedmann's original models probably were for pressureless dust, but now we lump everything together, including components with pressure, under the term FRW models.