Having trouble with this one anyone can give some insight?

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The discussion centers on a physics problem involving the heating of coffee in a glass beaker and the calculation of spilled volume due to thermal expansion. The initial and final temperatures of the coffee are provided, along with the volume of the beaker. Participants discuss the appropriate equation for volume change due to temperature increase and the coefficient of volume expansion for both coffee and Pyrex glass. Clarification is sought regarding the volumetric expansion coefficient, with suggestions that the coefficient for Pyrex can be ignored in this context. The conversation emphasizes the importance of accurate values and proper application of thermal expansion principles.
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Homework Statement


During an all-night cram session, a student heats up a 0.360 liter (0.360 x 10- 3 m3) glass (Pyrex) beaker of cold coffee. Initially, the temperature is 18.1 °C, and the beaker is filled to the brim. A short time later when the student returns, the temperature has risen to 94.6 °C. The coefficient of volume expansion of coffee is the same as that of water. How much coffee (in cubic meters) has spilled out of the beaker?

Homework Equations



dV = V0 â (t1 - t0)

therefore

0.00036*0.000214(of water?)(94.6-18.1)
=
dV = V1 - V0 = change in volume

= answer

is this the correct equation?

The Attempt at a Solution

 
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And what is the coefficient of expansion for Pyrex glass ?
 
BvU said:
And what is the coefficient of expansion for Pyrex glass ?

4.0(10-6 m/(m K))*)
 
Which means it can be ignored and your approach is imho a good start.
Now I look at the value for â (usually the volumetric expansion coefficient is denoted with the symbol ##\beta##) and compare with the table here .
Notice something ? Where does your value come from ?

By the way, I forgot:

Hello James, and welcome to PF :smile: !
 
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