Having trouble writing down a metric in terms of metric tensor in matrix form?

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Discussion Overview

The discussion focuses on expressing the FLRW metric in matrix form using the metric tensor. Participants explore the representation of the metric in terms of its coefficients and the corresponding matrix structure, addressing both the diagonal and off-diagonal elements.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant requests clarification on writing the FLRW metric in matrix form, providing the metric expression for context.
  • Another participant outlines how to represent the line element as a sum of terms involving coefficients, indicating their placement in a matrix.
  • A subsequent reply provides a specific matrix representation of the metric tensor, detailing the arrangement of coefficients based on the indices of the coordinates.
  • Another participant points out corrections regarding the inclusion of minus signs in the matrix representation, suggesting that some terms were initially misrepresented.
  • A later reply acknowledges the correction and expresses gratitude for the clarification.

Areas of Agreement / Disagreement

Participants engage in a collaborative effort to refine the representation of the metric, with some corrections made regarding the signs in the matrix. However, there is no explicit consensus on a final form, as the discussion includes corrections and refinements without a definitive resolution.

Contextual Notes

Some participants note missing assumptions regarding the coefficients and their placement in the matrix, as well as unresolved details about the representation of off-diagonal terms.

zeromodz
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Can someone please explain to me how exactly you write down a metric, say the FLRW metric in matrix form. Say we have the given metric here.

ds^2 = dt^2 - R(t)^2 * [dw^2 + s^2 * (dθ^2 + sin^2(θ)dΦ^2)]

Thank you.
 
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Let the coordinates be q1,q2,q3,q4.

The line element will be a sum of terms like C12dq1dq2.

In matrix form, C12 will be in row 1 column 2 of the matrix.

Edit: See Rasalhague's post for the correct version. I forgot the 1/2 for the off-diagonal terms.
 
Last edited:
In your example, if q0 = t, q1 = w, q2 = θ, q3 = Φ (where superscripts are indices), then the matrix of coefficients will be as follows, with superscript 2 denoting an exponent:

[tex]\begin{pmatrix}<br /> 1 & 0 & 0 & 0\\ <br /> 0 & R(t)^2 & 0 & 0\\ <br /> 0 & 0 & (R(t) \cdot s)^2 & 0\\ <br /> 0 & 0 & 0 & (R(t)\cdot s \cdot \sin(\theta))^2<br /> \end{pmatrix}[/tex]

= diag(1,0,0,0) - R(t)2[diag(0,1,0,0) + s2(diag(0,0,1,0)+diag(0,0,0,sin(θ)2)].

Here diag(a,b,c,d) denotes a diagonal 4x4 matrix with diagonal entries as indicated, from top left to bottom right.

In general, given an expression of the form

[tex]ds^2 = ...,[/tex]

where the values of the indices are not equal, the scalar coefficients in each term of the form

[tex]A \, dx^\mu dx^\nu \enspace (\text{no summation} )[/tex]

(EDIT: Ignore the words "no summation" - a relic of previous version which I forgot to remove before posting. Sorry.) correspond to matrix entries

[tex]g_{\mu\nu} = \frac{1}{2} A.[/tex]

And where the values of the indices are equal, the scalar coefficients in each term of the form

[tex]B \, (dx^\mu)^2[/tex]

correspond to matrix entries

[tex]g_{\mu\mu} = B.[/tex]
 
Last edited:
Rasalhague accidentally missed some minus signs:

[tex]\begin{pmatrix}<br /> 1 & 0 & 0 & 0\\ <br /> 0 & -R(t)^2 & 0 & 0\\ <br /> 0 & 0 & -R(t)^2 \, s^2 & 0\\ <br /> 0 & 0 & 0 & -R(t)^2 \, s^2 \, \sin^2\theta<br /> \end{pmatrix}[/tex]​
 
Oopsh... Thanks for the correction, Dr Greg!
 

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