Heat absorbed by an ideal gas in a cycle

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SUMMARY

The discussion focuses on the heat absorbed by an ideal gas during a thermodynamic cycle consisting of adiabatic and isothermal processes. Specifically, the heat absorbed during the adiabatic process AC is zero, while the heat absorbed during the isothermal process AB is calculated using the formula \( RT\ln \frac{V_3}{V_1} \). The heat absorbed during process CB is expressed as \( C_p \Delta T = -\frac{\gamma}{\gamma -1} (P_2V_3 - P_2V_2) \). Despite these calculations, the participants conclude that the total heat absorbed does not match any of the provided options, indicating a potential misunderstanding or miscalculation in the problem setup.

PREREQUISITES
  • Understanding of thermodynamic processes, specifically adiabatic and isothermal processes.
  • Familiarity with the ideal gas law and its applications.
  • Knowledge of specific heat capacities, particularly \( C_p \) and \( \gamma \) (the heat capacity ratio).
  • Ability to manipulate logarithmic equations in the context of thermodynamics.
NEXT STEPS
  • Review the derivation of heat transfer equations for adiabatic and isothermal processes.
  • Study the implications of the ideal gas law in thermodynamic cycles.
  • Learn about the significance of the heat capacity ratio \( \gamma \) in different gas processes.
  • Explore common pitfalls in thermodynamic calculations and how to avoid them.
USEFUL FOR

Students and professionals in thermodynamics, particularly those studying ideal gas behavior and thermodynamic cycles. This discussion is beneficial for anyone looking to deepen their understanding of heat transfer in gas processes.

Isomorphism
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Homework Statement


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Homework Equations

and the attempt at a solution:[/B]
AC is adiabatic and AB is isothermal.

Heat absorbed during process AC = 0 (adiabatic).
Heat absorbed during process CB = [tex]C_p \triangle T=-\frac{\gamma}{\gamma -1} (P_2V_3 - P_2V_2)[/tex]
Heat absorbed during process BA = [tex]RT\ln \frac{V_3}{V_1}[/tex]

Summing it up, does not give any of the options. What went wrong?
 
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I agree with your answer. In my judgment nothing went wrong.
 
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