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Heat absorbed by an ideal gas in a cycle

  1. Nov 13, 2016 #1
    1. The problem statement, all variables and given/known data

    2. Relevant equations and the attempt at a solution:
    AC is adiabatic and AB is isothermal.

    Heat absorbed during process AC = 0 (adiabatic).
    Heat absorbed during process CB = [tex] C_p \triangle T=-\frac{\gamma}{\gamma -1} (P_2V_3 - P_2V_2) [/tex]
    Heat absorbed during process BA = [tex] RT\ln \frac{V_3}{V_1} [/tex]

    Summing it up, does not give any of the options. What went wrong?
  2. jcsd
  3. Nov 13, 2016 #2
    I agree with your answer. In my judgment nothing went wrong.
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