Heat and Ideal Gas Homework: Point 3 Pressure Calculation

[element72]

Homework Statement

Look at picture

The Attempt at a Solution

For V at point 3 I got 4.52 x 10^(-2)
For V at point 2 I assumed it was the same as Point 1, but this is where it gets confusing because if I assume that, then does point 3 have the same pressure as point 1?

This was actually on my test I just took! and that's all the given info she gave me. Please let me know what you get.

 

[dacruick]

Show me your work?

 

[element72]

Show me your work?

I used the formula PV = nRT for Point 1 and solved for V1 = 2.46x10^(-2)
I made the assumption that V2 = V1

Then I used the adiabatic formula, TV^(gamma - 1) = constant for Point 2 to Point 3.
I just plugged in everything and got V3 = 4.52 x 10^(-2)

Do you really want me to type out all the steps I did? because I am doing this at least 3 times over and I'm getting the same thing.

 

[dacruick]

Well you typing out all of the steps allows me to help you without doing the steps myself. I'm lazy enough to not want to do the question, but I am still willing to help lol.

Your method looks right, and the answer coincides with your graph. So I say its good.