Heat diffusion into an infinite rod

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SUMMARY

The discussion centers on the mathematical modeling of heat diffusion in an infinite rod, specifically using the heat equation dT/dt = k * d²T/d²x. The conversation highlights the concept of heat kernels and introduces a proposed function T = e^(-k*x/t) for a rod with one end maintained at a constant temperature. The correct solution involves the complementary error function of x/sqrt(t), which satisfies the heat equation and illustrates the slow nature of heat diffusion in solids. References to authoritative texts such as "Transport Phenomena" by Bird, Stewart, and Lightfoot are provided for further exploration.

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  • Understanding of the heat equation and its components
  • Familiarity with differential equations
  • Knowledge of complementary error functions
  • Basic concepts of heat transfer in solids
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  • Learn about complementary error functions and their role in heat diffusion
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  • Investigate numerical methods for solving differential equations related to heat transfer
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kairama15
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I have recently been curious about heat diffusion. If there is space in one dimension with any kind of temperature dispersed throughout, then the heat equation states that the derivative of the temperature with respect to time at any point equals some constant (k) multiplied by the second derivative of temperature with respect to space at that point... or:
dT/dt=k*d^2T/d^2x
This is expressed in the Wikipedia page regarding the heat equation. This is intuitive, and I understand this differential equation.
I was reading up on ‘heat kernels’, which seem to be a tiny point of heat inside an object (let’s say a long metal rod with a point somewhere in it that is very hot). Through a lot of math it can be shown that the function that describes the temperature as a function of position throughout the rod and time is:
(1/sqrt(4*pi*k*t)) * e^(-x^2/(4*k*t)) (found on wikipedia)
This function makes sense. At time t, the function expresses the temperature as being concentrated at a point in the rod and as time goes by the temperature moves out of the point along the length of the rod.
However, I am curious if anyone has ever attempted to formulate an equation for temperature as a function of position and time f(x,t) for an infinitely sized rod whose one end is attached to an object that remains at constant temperature? So, instead of a heat kernel being placed somewhere in the middle of the rod, an object of always constant temperature is placed at one end of the rod, slowly heating the rod from one end. I have a suspicion the function will likely be something like:
T=e^(-k*x/t)
but I don't know. Does anyone know if a solution was ever developed for this?
 
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The solution is a complimentary error function involving ##x/\sqrt{t}##. See Transport Phenomena by Bird, Stewart, and Lightfoot or Conduction of Heat in Solids by Carslaw and Jaeger for the solution, or Heat Transmission by McAdams or any other heat transfer book.
 
Thank you very much for your response. The complimentary error function of x/sqrt(t) does indeed satisfy the differential equation dT/dt=kd^2T/d^2x. How beautiful. This equation seems to suggest that heat diffusion throughout a rod or a substance is really slow, especially since the time component is 1/sqrt(t) inside of the complimentary error function which goes to 0 quite fast for increasing x.

Thank you so much for your response and helping me understand the beautiful mathematical description of this natural phenomenon. Are you 'responders' paid by physics forums, or do you respond as a hobby, or a little of both? I'm very happy there are people that can respond to my curious questions. I think math and physics are beautiful like art, so I like exploring them. And I want to know what your 'responders' backgrounds are.
 
kairama15 said:
Thank you very much for your response. The complimentary error function of x/sqrt(t) does indeed satisfy the differential equation dT/dt=kd^2T/d^2x. How beautiful. This equation seems to suggest that heat diffusion throughout a rod or a substance is really slow, especially since the time component is 1/sqrt(t) inside of the complimentary error function which goes to 0 quite fast for increasing x.

Thank you so much for your response and helping me understand the beautiful mathematical description of this natural phenomenon. Are you 'responders' paid by physics forums, or do you respond as a hobby, or a little of both? I'm very happy there are people that can respond to my curious questions. I think math and physics are beautiful like art, so I like exploring them. And I want to know what your 'responders' backgrounds are.
Physics Forums staff are not paid. It is totally voluntary. Our only reward is being able to help members like yourself.

There are detailed bios of all the PF staff available in our forums.
 
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Thank you for your time helping people with math/physics. I think it's awesome. There should be more people like you folks.
 

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