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## Homework Statement

A box of books that weighs 40N is dragged at a speed of 1.5 m/s across a rough floor. If the coefficient of friction between the floor and the box is 0.20, what is the rate at which heat energy is dissipated?

## Homework Equations

Friction: f=μN

Work: W=F*d

Power: P=W/t

## The Attempt at a Solution

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My assumption would be if the units of power are watts, or kgm

^{2}/s

^{3}, breaking that up would be :

kg*m/s

^{2}*m/s

and the box weighs 40N, so kg*m/s

^{2}=40, and v=1.5m/s

With the coefficient of friction being 0.20,

would the answer be 40*1.5*0.2= 12W ?