# Heat from an A/C inverter calculation more than energy consumed?

1. Oct 25, 2014

### pd2905

Hi guys can anyone please tell me that it is possible with an air conditioner of type inverter to put less energy than what the piece is receiving as heat. So let's say that on the inverter it says output KWh/ input KWh =4.

Henthalpy= G+TS
4*Hinput= Houtput inside the house

So to heat my house I use 4 times less energy if I just used a normal electric heater or this is what they write in product description?

2. Oct 25, 2014

### NTW

If you use a standard electric heater, 100% of the electric energy consumed is converted in heat.

But, in if a 'heat pump', you use the electric energy to drive a compressor, and the machine converts low-temperature heat, available in the external surroundings, in the external air, mainly, to high temperature heat, that may be used to heat your room. The 'transportation cost' is lower than the energy costs of a resistance heater of the same heating power. How much lower depends on the difference of inside/outside temperatures. The larger the difference, the smaller the advantage with respect to a resistance heater.

A refrigerator (or heat pump, that is the same) is esentially a thermal engine working in reverse. Instead of taking heat from a high-temperature place, producing useful mechanical work, and discharging that low-temp heat in a low-temperature place, the refrigerator/heat pump takes low-temp heat from a low temperature place, injects mechanical power, and places the resulting high-temp heat in a high temperature environment...

I believe that using '4 times less energy' may be too optimistic...

Last edited: Oct 25, 2014
3. Oct 25, 2014

### Staff: Mentor

I guess that what you are describing is more commonly known as a heat pump. If that is the case, then indeed you get more heat out than the electricity input, as additional heat is extracted from the outside air. This is more efficient than direct electric heating.

4. Oct 25, 2014

### NTW

This two very clear pictures are from 'The Second Law', by Henry Bent:

5. Oct 26, 2014

### pd2905

For an ideal heat pump cycle:

COP = TH/(TL-TH)
source wikipedia.

6. Oct 26, 2014

### pd2905

Thanks for the reply DrClaude, just to add to your thing there is heat pump systems that are air-water, water-water and air-air( air conditioner inverter).
For an ideal heat pump cycle:

COP = TH/(TL-TH)
source wikipedia.

7. Oct 26, 2014

### pd2905

How does delta S stay zero in both directions? So the reversed Carnot is the refrigeration cycle, but do these heat pumps use only one cycle, and is it possible that they have some newer technologies so that the efficiency of an air-air heat pump reaches 4 or 5 up to -20 degrees C?

8. Oct 26, 2014

### NTW

400K reservoir ---> ΔE (cal) = -1200 cal ΔS (cal/K) = -3 cal/K
300K reservoir ---> ΔE (cal) = +900 cal ΔS (cal/K) = +3 cal/K
Weight -------------> ΔE (cal) = +300 cal

Balance -----------> ΔE = 0 cal ΔS = 0 cal/k