Heat transfer: All 3 modes together

In summary, you will use the energy absorbed from the sun, radiant energy emitted from the plate, and convection energy loss to calculate the temperature rise on a steel plate in the sun.
  • #1
chetanladha
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Hi.
How can i find out the temperature rise in a steel plate of known dimensions, when exposed to sunlight, losing heat to air flowing over it by convection, and heat getting transferred to another body by convection?
I hope to hear about the different approaches that could be taken.

Thanks in advance.
 
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  • #2
Basically, you will perform an energy balance from radiation absorbed from the sun, radiant energy emitted from the plate, and convection energy loss as follows:

Energy absorbed by sun (Es) = absorptivity X solar radiation power density

For a steel plate, you can use absorptivity = 0.5. A good average value of energy from the sun at the surface of the Earth is 750 watt / m^2.

Now the plate will "re-radiate" energy back into space as follows

Er = emmissivity * Stefan Boltzmann constant X surface area of plate (plate surface temperature ^ 4 - sky temperature ^ 4)

you can use emmissivity = 0.21 for your steel plate and sky temperature (not ambient temperature) = - 5 C. Make sure your temperatures are in Kelvin and Rankine.

Finally, use Newton's law of cooling for the convection:

Econv = A * h * (T-surface - T-ambient)

And you can find h from a vertical plate natural convection correlation.

The solution is trial-and-error. Assume a value of T-surface until:

Es = Er + Econv
 
  • #3
Many Thanks for your response.
Can u please explain why have u used sky temperature radiated energy, and not the ambient temperature.

Er = emmissivity * Stefan Boltzmann constant X surface area of plate (plate surface temperature ^ 4 - sky temperature ^ 4)

Also, is it appropriate to use sky temperature as -5, or should it be 3 Kelvin?
 
  • #4
chetanladha said:
Many Thanks for your response.
Can u please explain why have u used sky temperature radiated energy, and not the ambient temperature.

Er = emmissivity * Stefan Boltzmann constant X surface area of plate (plate surface temperature ^ 4 - sky temperature ^ 4)

Also, is it appropriate to use sky temperature as -5, or should it be 3 Kelvin?

Atmospheric emmision is often estimated as blackbody, hence the "sky" temperature. You want to use an average temperature for the atmosphere so 3 K is too low (would suggest - 5C to -10C).
 
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FAQ: Heat transfer: All 3 modes together

1. What are the three modes of heat transfer?

The three modes of heat transfer are conduction, convection, and radiation. Conduction is the transfer of heat through direct contact between two objects. Convection is the transfer of heat through the movement of fluids. Radiation is the transfer of heat through electromagnetic waves.

2. How do these modes of heat transfer work together?

In most situations, all three modes of heat transfer are present and work together to transfer heat. For example, when cooking on a stovetop, heat is transferred through conduction from the burner to the pot, convection as the heated water moves and circulates, and radiation as heat is emitted from the stove.

3. What factors affect the rate of heat transfer?

The rate of heat transfer is affected by the temperature difference between the two objects, the thermal conductivity of the materials involved, the surface area of contact, and the distance between the objects.

4. How is heat transfer important in daily life?

Heat transfer is essential in maintaining comfortable living conditions, such as heating and cooling homes and buildings. It is also crucial in cooking, transportation, and various industrial processes.

5. Can heat transfer be controlled?

Yes, there are various ways to control the rate of heat transfer, such as using insulation to reduce heat loss or gain, adjusting the temperature difference between objects, and using materials with different thermal conductivities.

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