Heat transfer: All 3 modes together

Click For Summary

Discussion Overview

The discussion centers on calculating the temperature rise in a steel plate exposed to sunlight while accounting for heat loss through convection to the air and heat transfer to another body. Participants explore various approaches to perform this calculation, including energy balance methods and the use of specific temperature values.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant suggests performing an energy balance that includes energy absorbed from sunlight, energy re-radiated, and convection energy loss.
  • It is proposed that the absorptivity of the steel plate is 0.5 and that the average solar radiation power density is 750 watt/m².
  • Another participant questions the use of sky temperature instead of ambient temperature in the energy balance equation, seeking clarification on the appropriateness of using -5°C versus 3 K for sky temperature.
  • A response indicates that atmospheric emission is often estimated as a blackbody, suggesting that a sky temperature of -5°C to -10°C is more appropriate than 3 K.

Areas of Agreement / Disagreement

Participants express differing views on the appropriate temperature to use for sky temperature in calculations, indicating that there is no consensus on this aspect of the discussion.

Contextual Notes

Participants have not resolved the assumptions regarding the choice of sky temperature and its implications for the energy balance calculations.

chetanladha
Messages
59
Reaction score
0
Hi.
How can i find out the temperature rise in a steel plate of known dimensions, when exposed to sunlight, losing heat to air flowing over it by convection, and heat getting transferred to another body by convection?
I hope to hear about the different approaches that could be taken.

Thanks in advance.
 
Engineering news on Phys.org
Basically, you will perform an energy balance from radiation absorbed from the sun, radiant energy emitted from the plate, and convection energy loss as follows:

Energy absorbed by sun (Es) = absorptivity X solar radiation power density

For a steel plate, you can use absorptivity = 0.5. A good average value of energy from the sun at the surface of the Earth is 750 watt / m^2.

Now the plate will "re-radiate" energy back into space as follows

Er = emmissivity * Stefan Boltzmann constant X surface area of plate (plate surface temperature ^ 4 - sky temperature ^ 4)

you can use emmissivity = 0.21 for your steel plate and sky temperature (not ambient temperature) = - 5 C. Make sure your temperatures are in Kelvin and Rankine.

Finally, use Newton's law of cooling for the convection:

Econv = A * h * (T-surface - T-ambient)

And you can find h from a vertical plate natural convection correlation.

The solution is trial-and-error. Assume a value of T-surface until:

Es = Er + Econv
 
Many Thanks for your response.
Can u please explain why have u used sky temperature radiated energy, and not the ambient temperature.

Er = emmissivity * Stefan Boltzmann constant X surface area of plate (plate surface temperature ^ 4 - sky temperature ^ 4)

Also, is it appropriate to use sky temperature as -5, or should it be 3 Kelvin?
 
chetanladha said:
Many Thanks for your response.
Can u please explain why have u used sky temperature radiated energy, and not the ambient temperature.

Er = emmissivity * Stefan Boltzmann constant X surface area of plate (plate surface temperature ^ 4 - sky temperature ^ 4)

Also, is it appropriate to use sky temperature as -5, or should it be 3 Kelvin?

Atmospheric emmision is often estimated as blackbody, hence the "sky" temperature. You want to use an average temperature for the atmosphere so 3 K is too low (would suggest - 5C to -10C).
 
Last edited:

Similar threads

  • · Replies 34 ·
2
Replies
34
Views
6K
Replies
10
Views
3K
Replies
15
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 34 ·
2
Replies
34
Views
5K
Replies
7
Views
3K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K