Heat transfer and combustion correlations

In summary, the two correlations can be similar if the heat transfer coefficient is multiplied by the nusselt number.
  • #36
Rogue said:
##0.0044h= \frac {(2.816\times 10^-5)}{d} 0.53 (0.2355 \times 1.0421 d^{0.75}(T_s - T_f)^{0.25} 1.7698 ) (0.915)##

Would this be a step in the right direction?
Yes. This is basic high school algebra.
 
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  • #37
Chestermiller said:
Yes. This is basic high school algebra.

Bit harsh there Chet, but thanks.
I had just solved this, guess I need to try keep thinking straightforward rather than over complicating it. :)
 
  • #38
Rogue said:
Bit harsh there Chet, but thanks.
I had just solved this, guess I need to try keep thinking straightforward rather than over complicating it. :)
Sorry. I didn't mean to be harsh. I was just helping my grandson study for the SATs yesterday, and this kind of exponential algebra was one of the things the study guide touched upon.
 
  • #39
Chestermiller said:
Sorry. I didn't mean to be harsh. I was just helping my grandson study for the SATs yesterday, and this kind of exponential algebra was one of the things the study guide touched upon.
No worries.
 

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