Heater causes room temp to rise

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To determine the temperature rise in a room heated by a heater supplying 1.8 x 10^6 J/h, the specific heat capacity of air is essential. First, calculate the mass of the air in the room, which has a volume of 89.7 m^3. Using the formula for change in energy, you can relate the energy supplied by the heater to the mass of the air and the temperature change. Ensure to maintain consistent units throughout the calculations. This approach will yield the desired temperature increase after one hour of heating.
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Here's yet another problem causing me trouble. I just don't understand(yet again) how to begin the problem. A little nudge in the right direction would be very much appreciated!

If a heater supplies 1.8 x 10^6 J/h to a room 6.5m X 4.6m X 3.0m containing air at 20 deg C and 1atm, by how much will the temperature rise in one hour, assuming no heat losses to the outside.


I obviously already figured the volume to be V=89.7 m^3...but lost as what to do next.

Thanks a ton!

Brad
 
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You need the specific heat capacity of air, which is measured in joules per gram per kelvin. Find out how much that air weighs, and then you should be able to calculate what you want with the simple formula:

change in energy = (specific heat capacity)*(mass)*(change in temperature)

Watch your units!
 
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