# Heavily Damped Oscillator Equation

1. Feb 3, 2016

### RJLiberator

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

They tell me the hint, and to use the simplification. I assume when they say (1+y)^n they take y to be in general, anything. It was confusing at first to see a y in the format when no y was present in any of the previous equations.

So, we know ϒ^2/4 >> w_0^2
So, could we say α^2 = ϒ^2/4 -w_0^2 can turn into α^2 = ϒ^2/4 => α = ϒ/2.
But this is not of the form α = C(1+y)^n.

So, we know ϒ = b/m, but that doesn't seem to help too much as α = b/2m is still not in that form.

Any hints on how I can start this off on the right way? I have a lot of equations in front of me and I feel with a good start up hint ill be off to the races.

2. Feb 4, 2016

### Orodruin

Staff Emeritus
Read the given hint. It is there for a reason. You have only kept the leading term and not the first order correction.

I also disagree with the problem, I find it extremely intuitive that an overdamped system decays slower.

3. Feb 4, 2016

### RJLiberator

α^2=(ϒ^2/4)-w_0^2 and we want it in the form α = C(1+y)^n

I'm not quite sure what you mean with this quote.

The only way I can think of it is if we immediately take a square root of both sides.

α = sqrt(ϒ^2/4-w_0^2)

This is somewhat like what the hint desires, but I feel like I won't get anywhere with this (As ive tried some calculations with this).

I also did as well.

4. Feb 4, 2016

### Orodruin

Staff Emeritus
Rewrite the square root as an exponent ....

5. Feb 4, 2016

### RJLiberator

Ah, so you are suggesting there is more here.

α = sqrt(ϒ^2/4-w_0^2)
α = [ϒ^2/4-w_0^2]^(1/2)
In this case, C = 1
But, we need it to be in the form (1+y)^n
So, perhaps let's try to factor out a ϒ^2/4 from both terms
So we get
α = ϒ/2[1-4*w_0^2/ϒ^2]^(1/2)

Now it is appearing to be in correct form.
So,
α = ϒ/2[1-(1/2)*4*w_0^2/ϒ^2]

Simplifying we get
α = [ϒ/2-w_0^2/ϒ]

Oh my god.
I just solved it.

I love math. I also love you.
Why oh why did this take me hours.

6. Feb 4, 2016

### Orodruin

Staff Emeritus
Maybe this particular type of series expansion is not fundamental in your research subject - it is in mine.