Height, angles, and projectiles

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SUMMARY

The discussion centers on the physics problem of determining the maximum height a projectile can reach when fired from a spring-loaded gun at a 45-degree angle from the vertical. The correct answer is derived using the principles of conservation of energy and Newton's second law. The maximum height achieved by the projectile is h/2, as the vertical component of the initial velocity is halved when the angle is adjusted from vertical to 45 degrees.

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  • Understanding of projectile motion
  • Knowledge of conservation of energy principles
  • Familiarity with Newton's second law
  • Basic trigonometry for angle calculations
NEXT STEPS
  • Study the principles of projectile motion in detail
  • Learn about conservation of energy in mechanical systems
  • Explore Newton's laws of motion and their applications
  • Review trigonometric functions and their relevance in physics
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Students studying physics, educators teaching mechanics, and anyone interested in understanding projectile motion and energy conservation principles.

FrenchAtticus
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Homework Statement



A spring-loaded gun can fire a projectile to a height h if it is fired straight up.
If the same gun is pointed at an angle of 45 degrees from the vertical, what maximum height can now be reached by the projectile.

1. h _
2. h / 2\/2
3. h / 2 _
4. h / \/2
5. h / 4

2. The attempt at a solution

I believe it would be h / 2, but I'm not sure why other than the fact that 90/2=45 and the heights would therefore be relative.
 
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Welcome to PF!

FrenchAtticus said:
A spring-loaded gun can fire a projectile to a height h if it is fired straight up.
If the same gun is pointed at an angle of 45 degrees from the vertical, what maximum height can now be reached by the projectile.

Hi FrenchAtticus! Welcome to PF! :smile:

Hint: use conservation of energy, and Newton's second law horizontally. :wink:
 

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