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So I get Δp=10^-35*10^13 or

Δp=10^-22 and p=mv, so

Δv=10^10

This is where I am confused. I don't know how to think about the Δv. What values do we choose for v final and v initial?

- Thread starter jaydnul
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- #1

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So I get Δp=10^-35*10^13 or

Δp=10^-22 and p=mv, so

Δv=10^10

This is where I am confused. I don't know how to think about the Δv. What values do we choose for v final and v initial?

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- #5

bhobba

Mentor

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Where they collided was not known to much accuracy.They also showed where the particles actually collide( to be precise, made to collide).

The way such things are calculated is by so called in and out states. We know the states going in, and calculate the transition probabilities of states going out - what's going on in between, and exactly where it occurs, we don't know.

Interestingly this was one of the first things figured out in QM by Max Born leading to the statistical interpretation:

http://hermes.ffn.ub.es/luisnavarro/nuevo_maletin/Born_1926_statistical_interpretation.pdf

Thanks

Bill

- #6

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You might find this of interest:

https://en.wikipedia.org/wiki/Atomic_orbital

especially :

https://en.wikipedia.org/wiki/Atomi...tions_to_the_Heisenberg_Uncertainty_Principle

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Thanks

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