Help calculating the voltage in a capacitor when t->infinite

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SUMMARY

The voltage across a capacitor, denoted as Vc(t), approaches a steady state as time approaches infinity (t → ∞). Initially, Vc(0) is 6V, and when the switch is opened, the capacitor behaves as an open circuit, preventing current flow. Contrary to the assumption that Vc(∞) equals 0V, the voltage stabilizes at a value determined by the resistor network in the circuit. The final voltage can be calculated by analyzing the voltage present at the capacitor's terminals when it is removed from the circuit.

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  • Understanding of capacitor behavior in DC circuits
  • Knowledge of resistor networks and voltage division
  • Familiarity with the concept of steady-state in electrical circuits
  • Basic principles of circuit analysis using ideal voltmeters
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Electrical engineers, students studying circuit theory, and anyone involved in analyzing capacitor behavior in DC circuits will benefit from this discussion.

lucasLima
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Hello Everyone!
So, I need to calculate the voltage in the capacitor, let's call it Vc(t).

For t=0- I know that there is no current in the capacitor. Did some calculations and I've found that Vc(0)=6v.
Now i need to know Vc(infinite)

But when the switch key is opened and the time goes to inifinte there is no current going through right? Because the capacitor works as an open circuit when there is no change.
So, is Vc(inifinite)=0?

Thanks in advance!
 
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lucasLima said:
But when the switch key is opened and the time goes to inifinte there is no current going through right? Because the capacitor works as an open circuit when there is no change.
So, is Vc(inifinite)=0?
It won't be infinite. There's no potential source in the circuit that's that large!

edit: Oops. My apologies, I misread your statement. No, the potential across the capacitor will not be zero.

Suppose you were to remove the capacitor from the circuit and replace it with an ideal voltmeter. What would it read?

Hint: With the switch open and the capacitor removed you should be able to simplify the resistor network. Maybe that will help you see the answer...
 
Last edited:
When t=∞ the current into/out of the capacitor becomes zero, meaning there will be no current to the capacitor via the resistor network. No current implies no voltage loss across the resistor feeding into the capacitor.

You could imagine removing the capacitor, and seeing what voltage exists where its terminals were; that's the voltage it will charge to by t=∞.
 

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