Help calculating torque of servo for gripper to hold part.

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Discussion Overview

The discussion revolves around calculating the minimal torque required for a servo to hold a gripper in place while supporting a load. It involves concepts of friction, weight, and torque calculations in a mechanical context.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation
  • Debate/contested

Main Points Raised

  • The initial calculation of friction force and total force acting on the load is presented, but the poster expresses uncertainty about its correctness.
  • Some participants challenge the formula used for calculating the friction force, suggesting that the correct approach involves the normal force and the coefficient of friction.
  • There is a discussion about the summation of vertical forces, with some participants emphasizing the need for equilibrium in the forces acting on the gripped object.
  • Participants propose different expressions for the normal force and torque, with some suggesting that torque is derived from the relationship between force and radius.
  • Corrections are made regarding the signs in the equations and the definitions of variables, indicating a need for clarity in the calculations.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct formulas and calculations for torque and friction. Multiple competing views and corrections are presented throughout the discussion.

Contextual Notes

There are unresolved assumptions regarding the definitions of variables and the relationships between forces. The calculations depend on the correct interpretation of the friction force and the normal force, which remain contested.

duzO
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Homework Statement


I have this problem. I'm trying to calculate the minimal servo torque for the gripper to hold the part in place.
http://img52.imageshack.us/img52/8784/96199865.jpg

Mass of load is 170grams. u friction between load and walls is 0.5.
the diameter of wheel on which the pegs that pull the grippers is 2cm.

Homework Equations


Force to squeeze * Friction between load and gripper walls > Mass of cube
Torque=Force * radius

The Attempt at a Solution


F(friction)=0.17kg x 0.5=0.085N
F(G)=0.17kg x G = 1.666N
F=F(f) + F(g)= 1.751N

T=1.751N*0.01m=0.01751Nm

This is probably wrong...

Any ideas?
 
Last edited by a moderator:
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duzO said:
F(f) = (0.17 kg)*0.5 = 0.085 N

duzO: This is not the correct formula for friction force. What is the general formula for friction force? Keep trying. Your formula for weight, F(g), is correct. Don't you want the summation of vertical forces on the gripped object to equal zero? Keep developing your formulas. You are getting close.
 
nvn said:
duzO: This is not the correct formula for friction force. What is the general formula for friction force? Keep trying. Your formula for weight, F(g), is correct. Don't you want the summation of vertical forces on the gripped object to equal zero? Keep developing your formulas. You are getting close.

https://www.physicsforums.com/mgc_gloss/latex_images/mgc_gloss_extexpl_39-4.png ?

so itll be F=umg . friction force=friction x normal force

so you are saying that mg=umg+F ?
1.66=0.833+F;
F=0.827N ?
 
Last edited by a moderator:
W acts downward. 2*Fs acts upward. Perform a summation of vertical forces, and set it equal to zero.
duzO said:
|Fs| ≤ mus*N

Very good. Now what is N? Write an expression for N. N comes from the servo, right? Try again.
 
nvn said:
W acts downward. 2*Fs acts upward. Perform a summation of vertical forces, and set it equal to zero.


Very good. Now what is N? Write an expression for N. N comes from the servo, right? Try again.

mg + 2(umN) = 0 ?

N=Torque/radius?

so Torque=gR/2u = 0.098Nm?
 
m*g should be negative, not positive. Fs = mu*N, not u*m*N. N = T/diameter, not T/radius. m = mass, mu = static coefficient of friction, N = normal force, Fs = frictional force. Try again.
 

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