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SUMMARY

The discussion centers on calculating kinetic energy (KE) for an object in a circular orbit and the necessary centripetal force to maintain that orbit. Key formulas mentioned include the centripetal force equation, ##F = m(v^2/r)##, and the relationship between kinetic energy and total mechanical energy, specifically ##E = U + T##. The conversation highlights the importance of understanding these concepts for analyzing circular motion in physics.

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  • Understanding of circular motion dynamics
  • Familiarity with kinetic energy and potential energy concepts
  • Knowledge of centripetal force calculations
  • Basic algebra for manipulating physics equations
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  • Study the derivation of centripetal force equations in circular motion
  • Explore the relationship between kinetic energy and potential energy in different motion scenarios
  • Learn about gravitational forces affecting circular orbits
  • Investigate real-world applications of circular motion in satellite dynamics
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Students of physics, educators teaching mechanics, and anyone interested in understanding the principles of circular motion and energy relationships in orbital dynamics.

fer Mnaj
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Homework Statement
If we have motion in a circular orbit of a body of mass m subject to the gravitational force of the Sun.
Consider the approximation for M >> m in which the Sun is located at the center of mass and μ = m.



How to show that the total mechanical energy associated with the movement of this body fulfills that
##E = −1 / 2U## ?

where U is the gravitational potential energy of m due to M
Relevant Equations
##-∇U= -G Mm/r^2##
Any idea? I am pretty lost
 
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Are you able to calculate the KE of the mass in a circular orbit?
 
Not really, can you explain it?
 
fer Mnaj said:
Not really, can you explain it?
What is needed to keep an object in a circular orbit?
 
fer Mnaj said:
Not really, can you explain it?
If you know that the orbit is circular, you have some formulas that could be used to express the required centripetal force.
 
##m (v^2/r)##
 
By ##E##, I suspect you mean kinetic energy instead of total mechanical energy.
 
why?
 
Because if ##E = U + T##, then for circular motion the following holds at all times: ##E = \frac{1}{2}U = -T##.
 
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