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## Main Question or Discussion Point

Hi everyone

Firstly this is not a homework question, i work in transport engineering. ( i do study part time which is why i sometimes post in the homework section)

Now to the problem.

I am trying to understand how to solve this problem, i already know the answer.

A train is travelling on straight & level track at 136.794kph.

It approaches a transition. The transition is 60m long.

Along the transition the Left Rail rises linearly over the length of the transition relative to the right Rail by 25mm.

Calculate the rate of change the left rail raises over the right in mm per sec over the 60m transition at 136.794kph.

i know that the answer is (25mm * 136.794kph) / (3.6 * 60m)

what i need help with is where does the 3.6 some from? and why do you times 25mm by 136.794kph?

can anyone explain

Thanks

Firstly this is not a homework question, i work in transport engineering. ( i do study part time which is why i sometimes post in the homework section)

Now to the problem.

I am trying to understand how to solve this problem, i already know the answer.

A train is travelling on straight & level track at 136.794kph.

It approaches a transition. The transition is 60m long.

Along the transition the Left Rail rises linearly over the length of the transition relative to the right Rail by 25mm.

Calculate the rate of change the left rail raises over the right in mm per sec over the 60m transition at 136.794kph.

i know that the answer is (25mm * 136.794kph) / (3.6 * 60m)

what i need help with is where does the 3.6 some from? and why do you times 25mm by 136.794kph?

can anyone explain

Thanks