1. The problem statement, all variables and given/known data Judy looks from her 20m high balcony to a swimming pool below, not directly below, but 3m out from the bottom of the building. If the pool is 6m wide. (a) How fast would she have to jump horizontally to land in the middle of the pool? (b) Judy's mass is 60 kg, what will be her increase in KE (compared to when she left the balcony) as she hits the water? 2. Relevant equations mgh=1/2mv^2 horizontal velocity must play a factor possibly d=1/2gt^2 3. The attempt at a solution The center of the pool is 6m out from the balcony (3m out plus 3m to center). I am very unsure of what to do beyond this. This is what I have started w... mgh=1/2mv^2 mgh= 1/2m(gt)2 (since gt=v)? divide by 2 then g's & m's cancel out ? leaving 2h=t^2 2(20m)=40 40 square root = 6.324s which is the time?? I am REALLY digging here!! help! I'm not sure the even helps get me closer to am answer.