What Price Should a Grocer Charge for Mixed Rice to Gain 16%?

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A grocer purchased 80 kg of rice at 13.50 per kg and 120 kg at 16 per kg, totaling a mixed cost price. To achieve a 16% profit margin, the selling price must be calculated based on the total cost of the rice mixture. Participants in the discussion emphasize the need to derive the cost price and selling price equations to determine the appropriate selling rate. The conversation highlights the importance of understanding cost calculations rather than relying solely on memorized formulas. Ultimately, the grocer must set a selling price that reflects a 16% increase over the calculated cost per kilogram of the rice mixture.
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a grocesser purchased 80 kg of rice at the rate of 13.50 per kg and mixed it with 120 kg rice at the amount of 16 per kg.at what rate per kg should he sell the mixture to gain 16%
 
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neha1 said:
a grocesser purchased 80 kg of rice at the rate of 13.50 per kg and mixed it with 120 kg rice at the amount of 16 per kg.at what rate per kg should he sell the mixture to gain 16%
Hi again neha1,

Please note that you must show some effort in attempting to solve the question yourself before we can help you.
 
am not aware of this cost price and selling price equations
 
neha1 said:
am not aware of this cost price and selling price equations
Neither am I, but I would imagine that you are expected to derive expressions for each individual case rather than remembering specific formulae.
 
What did he pay for all of the rice? How much rice did he buy? From that, how much did he pay "per kilogram" for the rice?

He wants to make a 16% gain. What price is 16% more than what he paid?
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Essentially I just have this problem that I'm stuck on, on a sheet about complex numbers: Show that, for ##|r|<1,## $$1+r\cos(x)+r^2\cos(2x)+r^3\cos(3x)...=\frac{1-r\cos(x)}{1-2r\cos(x)+r^2}$$ My first thought was to express it as a geometric series, where the real part of the sum of the series would be the series you see above: $$1+re^{ix}+r^2e^{2ix}+r^3e^{3ix}...$$ The sum of this series is just: $$\frac{(re^{ix})^n-1}{re^{ix} - 1}$$ I'm having some trouble trying to figure out what to...

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