Help Needed: Force Equations for Horizontal Component of Bigger Block

  • Thread starter Thread starter iMAGICIALoTV
  • Start date Start date
  • Tags Tags
    Force
Click For Summary
SUMMARY

The discussion centers on calculating the horizontal component of force for a system involving two blocks with different masses. The equation presented, \(\Sigma F_{x_1} = F_a - (f_k + N_2) = ma\), is used to analyze the forces acting on the blocks. The user attempts to find the normal force and friction but arrives at an incorrect value of 6.877 N. The correct approach involves calculating the gravitational force on the 0.4 kg object to determine the necessary upward friction and subsequently finding the normal force exerted by the 1.8 kg object.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of force components in physics
  • Familiarity with frictional force calculations
  • Basic algebra for solving equations
NEXT STEPS
  • Study the concept of normal force in multi-body systems
  • Learn about friction coefficients and their impact on motion
  • Explore gravitational force calculations for different masses
  • Review problem-solving techniques for physics equations
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone involved in mechanics, particularly those tackling problems related to force analysis in multi-body systems.

iMAGICIALoTV
Messages
11
Reaction score
0

Homework Statement



506ccf63e4b088f3c14d2617-micahwood50-1349308269219-untitled1.png


Homework Equations


I don't know if I set the equation for horizontal component of the bigger block correctly:

\huge{\Sigma F_{x_1} = F_a - (f_k + N_2) = ma}

If this is true then it seems that there is not enough given information to find F_a. Are there some other way?

The Attempt at a Solution


Find the normal force and friction, then substitute some variables, I guess? I got 6.877 N, but I know it's wrong...
 
Physics news on Phys.org
Somebody? Help me, please?
 
Find the force of gravity on the .4kg object. That'll give you the required upward friction. Then find the normal force that the 1.8kg object must exert on the .4kg object to get that required friction.
 

Similar threads

Replies
7
Views
2K
  • · Replies 24 ·
Replies
24
Views
2K
Replies
13
Views
3K
Replies
3
Views
662
  • · Replies 11 ·
Replies
11
Views
3K
Replies
31
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 12 ·
Replies
12
Views
4K
Replies
61
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K