Find the force between 2 blocks

In summary, after an inelastic collision, object A moves 2 meters to the right while object B moves 7 meters to the right.
  • #1
Helly123
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20
1. The problem statement, all variables and given/known data
20180503_214535.jpg


Homework Equations

The Attempt at a Solution


B at rest. A moves 7m/s and bump into B. Object A is frictionless. Object B not, coeff of friction = 0.2.
g = 9.8 m/s2
After collision both objects moves together with speed 2 m/s to the right.

Let refer C for force between objects. (What we have to find)

Object B as system
##C - F_{friction} ## = ##mass_B## . a

Object A as system
##F_A## - C = ##mass_A## . a

I am still confused to make fhe force system for B or A. How is the correct force system?

How to find that C? When we don't know ##F_A##?
Please help me..
 

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  • #2
This looks tricky.

Hint: work out what would happen if there were no friction. Assume an inelastic collision. What result do you get?
 
  • #3
PeroK said:
This looks tricky.

Hint: work out what would happen if there were no friction. Assume an inelastic collision. What result do you get?

Sigma F = Sigma m * a
F_A = (m_A + m_B) * a
Is it?
 
  • #4
Helly123 said:
Sigma F = Sigma m * a
F_A = (m_A + m_B) * a
Is it?

That's not an answer. Do you know how to solve the problem of an inelastic collision?

Also, what do you know about momentum?
 
  • #5
PeroK said:
That's not an answer. Do you know how to solve the problem of an inelastic collision?

Also, what do you know about momentum?
Ok let me think.
Momentum?

M1V1 + M2V2 = M1V1' + M2V2'
M1V1 + M2V2 = (M1 + M2)V'
 
  • #6
I have to say I'm confused as well. Are you sure this is the whole question?
 
  • #7
PeroK said:
I have to say I'm confused as well. Are you sure this is the whole question?
http://[url=https://ibb.co/diBMon]https://preview.ibb.co/jd8dZS/20180504_004628.jpgthis is the whole question. Hope it shows clear
[ATTACH=full]225086[/ATTACH]
 

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  • #8
Okay. That makes sense now. So, you've solved part 1).

What determines what happens in part 2)?
 
  • #9
PeroK said:
Okay. That makes sense now. So, you've solved part 1).

What determines what happens in part 2)?
Well... they both moving together.. now.. there is friction working and acceleration slow them down
 
  • #10
Helly123 said:
Well... they both moving together.. now.. there is friction working and acceleration slow them down

What slows them down?
 
  • #11
PeroK said:
What slows them down?
Friction at mass 2 right?
 
  • #12
Helly123 said:
Friction at mass 2 right?
Right. So evaluate that frictional force.
 
  • #13
haruspex said:
Right. So evaluate that frictional force.
5*9.8*0.2 = 9.8 N
 
  • #14
B as system
C - F_friction = Mass_B * a
 
  • #15
Helly123 said:
5*9.8*0.2 = 9.8 N
Yes.
Helly123 said:
B as system
C - F_friction = Mass_B * a
Yes.
What about the other block?
 
  • #16
haruspex said:
Yes.

Yes.
What about the other block?
F_A - C = Mass_A * a
 
  • #17
Helly123 said:
F_A - C = Mass_A * a
What is F_A?
 
  • #18
haruspex said:
What is F_A?
The force makes A move?
 
  • #19
Helly123 said:
The force makes A move?
That sounds rather pre-Newtonian. Forces make things accelerate.
What forces are acting on block A after the collision?
 
  • #20
haruspex said:
That sounds rather pre-Newtonian. Forces make things accelerate.
What forces are acting on block A after the collision?
Force of contact with b because of friction too?
Pre-Newtonian?
 
  • #21
Helly123 said:
Force of contact with b because of friction too?
You have the force of contact with B represented by C in your equation in post #16. I am asking about this mysterious FA in that equation. What is it? Where does it come from? We are told there is no friction between A and ground.
 
  • #22
haruspex said:
You have the force of contact with B represented by C in your equation in post #16. I am asking about this mysterious FA in that equation. What is it? Where does it come from? We are told there is no friction between A and ground.
Yes.. the force that moves A
Something that accelerate A to move into b?
 
  • #23
Maybe there is no F_A since we focus on the collision?
 
  • #24
Helly123 said:
Maybe there is no F_A since we focus on the collision?
The collision has happened. We are dealing with the subsequent acceleration. There is no FA.
So combine your equations for the two blocks and solve.
 
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  • #25
haruspex said:
The collision has happened. We are dealing with the subsequent acceleration. There is no FA.
So combine your equations for the two blocks and solve.
Ok. I will try
 

1. What is the formula for finding the force between two blocks?

The formula for finding the force between two blocks is F = μN, where F is the force, μ is the coefficient of friction, and N is the normal force.

2. What factors affect the force between two blocks?

The force between two blocks is affected by the coefficient of friction, the normal force, and the surface area of contact between the blocks.

3. How does the coefficient of friction affect the force between two blocks?

The coefficient of friction is a measure of how easily two surfaces slide against each other. A higher coefficient of friction means there is more resistance to motion, resulting in a greater force between the two blocks.

4. What is the normal force and how does it contribute to the force between two blocks?

The normal force is the force exerted by one object on another in a direction perpendicular to their surfaces. It contributes to the force between two blocks by counteracting the force of gravity and preventing the blocks from sliding apart.

5. How does the surface area of contact between two blocks affect the force between them?

The surface area of contact between two blocks affects the force between them by increasing or decreasing the amount of friction between the two surfaces. A larger surface area of contact results in a greater force, while a smaller surface area results in a smaller force.

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