Tension and acceleration for two blocks connected by pulley on inclined plane

[katzmeow9]

Homework Statement

Block A has mass m = 4.0 kg, and block B has mass m= 2.0 kg. The coefficient of kinetic friction between block B and the horizontal plane is 0.50. The inclined plane is frictionless at the angle 30 degrees and Block A sits on it. The pulley serves only to change the direction of the cord connecting the blocks. The cord has negligible mass. Find (a) the tension in the cord and (b) the magnitude of the acceleration of the blocks.

Homework Equations

FN = Fgx
Fg = mg
a = Fnet/m

The Attempt at a Solution

I found the normal force of block A to be 33.95 N and the Fg to be 39.2 N. For block B, FN should be 19.6 N and fk should be 9.8 N.

Now I'm just confused about what forces cause the tension force (I don't know what to add, subtract, etc. to get FT)

I need help tonight if possible!

 

[rl.bhat]

Take the components of mg along the inclined plane. It is in the downward direction. Find the net force acting on it.
Then the acceleration of the sliding body. Equate it to that of the body on the table.