- #1
CrazyNeutrino
- 100
- 0
I need help to take the time derivative of a physics equation.
The equation:
ME=1/2 mr^2 (dθ/dt)^2 +mgr θ^2/2
Where ME is the mechanical energy , m is the mass of the object, r is the radius of the path of the object and θ is the angle around the path.
Walter Lewin at MIT differentiates it and gets the result:
mr^2 (dθ/dt) (d^2 θ/dt^2)+mgr θ dθ/dt
Can someone please explain why this is so. I can't understand how that would be the derivative of the function. Please answer.
The equation:
ME=1/2 mr^2 (dθ/dt)^2 +mgr θ^2/2
Where ME is the mechanical energy , m is the mass of the object, r is the radius of the path of the object and θ is the angle around the path.
Walter Lewin at MIT differentiates it and gets the result:
mr^2 (dθ/dt) (d^2 θ/dt^2)+mgr θ dθ/dt
Can someone please explain why this is so. I can't understand how that would be the derivative of the function. Please answer.