Help with Calculus Homework: Find Tangent Plane, Intuitive Geometric Argument

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Homework Help Overview

The discussion revolves around finding the equation of the tangent plane at a specific point on the surface defined by the function z=f(x,y)=√(1-x²-y²). Participants are also tasked with providing an intuitive geometric argument to support their findings.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss their understanding of finding the tangent plane using the gradient and express confusion regarding the concept of a geometric argument. There is a question about whether stating that the tangent plane is locally linear qualifies as a geometric argument.

Discussion Status

Some participants are seeking clarification on the nature of geometric arguments and how they relate to the surface in question. One participant suggests that understanding the geometric figure represented by the surface could aid in intuitively grasping the tangent plane's equation.

Contextual Notes

There is an indication of difficulty with geometric interpretations, and participants are encouraged to explore the visual aspects of the surface to enhance their understanding.

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Homework Statement



1.Find the equation of the tangent plane at p=(0,0) on the surface z=f(x,y)=√(1-x²-y²)

p is a vector.

2.Give an intuitive geometric argument to support the result

Homework Equations




The Attempt at a Solution



So I have no problem finding the equation of the tangent line. I am supposed to use the gradient to find it. But I don't really understand the second question. What is a geometric argument?

Is it correct if I justify my answer by saying that the tangent plane is locally linear at p? Is that a geometric argument?

Somehow, I feel that it is just not enough.

Don't give me the answer please. Just a hind of what it means by "geometric argument."

Thank You
 
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Marioqwe said:

Homework Statement



1.Find the equation of the tangent plane at p=(0,0) on the surface z=f(x,y)=√(1-x²-y²)

p is a vector.

2.Give an intuitive geometric argument to support the result

Homework Equations




The Attempt at a Solution



So I have no problem finding the equation of the tangent line. I am supposed to use the gradient to find it. But I don't really understand the second question. What is a geometric argument?

Is it correct if I justify my answer by saying that the tangent plane is locally linear at p? Is that a geometric argument?
No. The surface z = f(x, y) = sqrt(1 - x^2 - y^2) represents a geometric figure. Your justification should involve this figure. If you knew what this figure was, you could work out the equation of the tangent plane in your head, without the use of calculus.
Marioqwe said:
Somehow, I feel that it is just not enough.

Don't give me the answer please. Just a hind of what it means by "geometric argument."

Thank You
 
Thank you very much. I'm still struggling with geometric interpretations but this surely helped.
 

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