Help with Change of variables and evaluating area?

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SUMMARY

The discussion focuses on evaluating the double integral I=∫∫D (x²−y²)dxdy over the region D defined by the inequalities 1≤xy≤2, 0≤x−y≤6, and x≥0, y≥0. The mapping u=xy and v=x−y successfully transforms D into the rectangle R=[1,2]×[0,6]. The Jacobian determinant is computed as \(\frac{\partial(x,y)}{\partial(u,v)}=\frac{1}{y+x}\), which is essential for applying the Change of Variables Formula. The integral I can then be expressed as the integral of f(u,v)=v over the rectangle R, facilitating easier evaluation.

PREREQUISITES
  • Understanding of double integrals and regions of integration.
  • Familiarity with the Change of Variables Formula in multivariable calculus.
  • Knowledge of Jacobians and their computation.
  • Basic proficiency in evaluating integrals over rectangular domains.
NEXT STEPS
  • Study the Change of Variables Formula in detail, focusing on its applications in multivariable calculus.
  • Learn how to compute Jacobians for various transformations in calculus.
  • Practice evaluating double integrals over different types of regions, including irregular shapes.
  • Explore examples of transforming coordinates in integrals, particularly using polar or other coordinate systems.
USEFUL FOR

Students and educators in calculus, particularly those focusing on multivariable calculus and integral evaluation techniques. This discussion is particularly beneficial for anyone learning about transformations and Jacobians in double integrals.

Suy
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Homework Statement



Let I=∫∫D (x2−y2)dxdy, where
D=(x,y): {1≤xy≤2, 0≤x−y≤6, x≥0, y≥0}
Show that the mapping u=xy, v=x−y maps D to the rectangle R=[1,2]χ[0,6].

(a) Compute \frac{\partial(x,y)}{\partial(u,v)} by first computing \frac{\partial(u,v)}{\partial(x,y)}.

(b) Use the Change of Variables Formula to show that I is equal to the integral of f(u,v)=v over R and evaluate.

Homework Equations



The Attempt at a Solution



(a) \frac{\partial(u,v)}{\partial(x,y)}=|-(y+x)|
so, \frac{\partial(x,y)}{\partial(u,v)}=\frac{1}{y+x}

(b)I have to evaluate I, but I have no idea how, please help!
 
Physics news on Phys.org
The change of variable converts the irregularly shaped domain D into the rectangle R, where you can evaluate I easier, to evaluate I perform the suggested change of variable, substitute in the jacobian, and evaluate over R, the jacobian you evaluated is correct, except it should be in terms of u, v, not x, y.
 

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